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OverLord2011 [107]
3 years ago
11

Two factors multiply to give you -48 and have a sum of -13. What are the factors? *

Mathematics
2 answers:
faltersainse [42]3 years ago
6 0
-16 and +3 is the correct answer to the question
Kobotan [32]3 years ago
3 0

Answer:

The corrrect answer is -16 and +3

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Help me please please
telo118 [61]

Answer:

see below

Step-by-step explanation:

Standard equation for a circle with center h,k and radius r

(x-h)^2 + (y-k)^2 = r^2

so for this one   center =  (1,2)   radius = 4

6 0
2 years ago
A 12 oz bottle of shampoo last 16 weeks. How long would you expect an 18 oz bottle to last
jenyasd209 [6]
If a 12 oz bottle of shampoo lasted for 16 weeks, we have a ratio of 12:16 which can be shortened to 3:4.

Now if we have 18 oz bottle we know that it's 1/2 more than 12 oz bottle, so the ratio will be also 1/2 more. So if it was 12:16, the new ratio will be:

12 + (1/2 * 12) : 16 + (1/2 * 16)
12 + 6 : 16 + 8
18 : 24

It means that 18 oz bottle should last for 24 weeks. Of course the ratio has to stay the same in its lowest form in both situations and as 18:24 can be shortened to 3:4, it proves it's correct :)
3 0
3 years ago
Write a doubles fact that can help you solve 6+5=11.
mario62 [17]
6+5=11 5+6=11 11-5=6 11-6=5
5 0
3 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
3 years ago
Explain how to solve for the rate in a simple interest equation if you are given the interest amount, the principal, and the tim
FrozenT [24]

Answer:

divide the interest amount by the product of the principal and time

Step-by-step explanation:

The simple interest formula is I = prt where I is the interest, p is the principal, r is the rate and t is the time (in years). Rewriting this formula so that r is the subject we get r = I / pt. Therefore the answer is divide the interest amount by the product of the principal and time.

8 0
3 years ago
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