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GuDViN [60]
3 years ago
10

Please I need help with these questions its Algebra

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0

1. 14/3

2. 9

4. 5

5. 15

(Sixth one is confusing sorry! But I hope you do well on it since I can't help you :|)

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The ratio of the length of a rectangle to its width is 8 to 5. If the longer side of the rectangle is 20ft, what is the length o
choli [55]

Answer: The answer is 12.5 ft.


Step-by-step explanation:  Given that there is a rectangle with ratio of its length to breadth 8 : 5. Also, the longer side of the rectangle is 20 feet. We are to find the length of the shorter side.

Let, '8x' and '5x' be the length and breadth of the rectangle respectively. Since length is the longer side, so we have

8x=20\\\\\Rightarrow x=\dfrac{20}{8}\\\\\\\Rightarrow x=2.5.

Therefore, width, length of the shorter side will be

W=5x=5\times 2.5=12.5~\textup{ft.}

Thus, the length of the shorter side is 12.5 ft.


6 0
3 years ago
Read 2 more answers
A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of
Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

5 0
3 years ago
What quadrant does the terminal side of this angle lie in?
Flura [38]

Answer:

D. quadrant III

Step-by-step explanation:

3 0
2 years ago
Please help and thank you
yuradex [85]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
The dogs in an animal parade are grouped by size. There are 18 small dogs, 12 medium-sized dogs, and 10 large dogs. If one dog i
ruslelena [56]

Answer:

0.3

Step-by-step explanation:

Given:

Number of small dogs = 18

Number of medium-sized dogs = 12

Number of large dogs = 10

To find: probability that a medium-sized dog will be chosen

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Total number of dogs = 18 + 12 + 10 = 40

Number of medium-sized dogs = 12

So,

probability that a medium-sized dog will be chosen = Number of medium-sized dogs/Total number of dogs = \frac{12}{40}=0.3

3 0
3 years ago
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