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GuDViN [60]
3 years ago
10

Please I need help with these questions its Algebra

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0

1. 14/3

2. 9

4. 5

5. 15

(Sixth one is confusing sorry! But I hope you do well on it since I can't help you :|)

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A particular psychological test is used to measure need for achievement. The average test score for all university students in O
Angelina_Jolie [31]

Answer:

Only B and C are always true.

Step-by-step explanation:

To analyse which statements are always true, we go through the process of finding confidence intervals for sample means, from the start.

Confidence Interval = (Sample mean) ± (Margin of error)

From this expression, it is evident that the margin of error determines how wide the confidence interval would be.

Sample Mean = 110 (given)

Margin of Error = (Critical value) × (Standard deviation of the distribution of sample means)

Since no information about the population standard deviation is provided, the critical value is obtained using t-distribution.

The critical value usually varies at different confidence levels and degree of freedoms.

The higher the confidence level, the higher the critical value and the higher the margin of error leading to a wider range.

Hence, a confidence interval of 95% will have a higher critical value than a confidence interval of 90%. Hence, statement C is proved once that 'for n = 100, the 95% confidence interval will be wider than the 90% confidence interval'.

After obtaining the critical value, we then obtain the standard deviation of the distribution of sample means or simply the standard error of the mean. This is given as

σₓ = σ/√n

where σ = standard deviation; which isn't given. The standard deviation might be high enough to guarantee that the Margin of error is high too for the confidence interval to contain 115 or low enough to ensure that the Margin of error is very small and the confidence interval will not contain 115.

Or the sample size might be high enough to make the standard error of the mean to be eventually small and lead to a small margin of error and the condidence interval will not contain 115.

The point is, it isn't always sure that the resulting interval.would contain 115. So, statement A isn't always true.

Then from σₓ = σ/√n,

n = sample size, a large sample size means a more narrow confidence interval and a small sample size means a wider sample size. This proves statement C.

The 95% confidence interval for n = 100 will be more narrow than the 95% confidence interval for n = 50.

Hence, Only B and C are always true.

Hope this Helps!!!

5 0
3 years ago
A container has
Aneli [31]

Answer:

there may be 16 but I am not sure

5 0
3 years ago
I don't know what is 4309/73
Alisiya [41]

Step-by-step explanation:

59 2/73

or 59.02 as the answer

4 0
3 years ago
Read 2 more answers
Given f(x)=2x2-3, find F(-3)
Paraphin [41]

Answer:

f(-3) = 15

Step-by-step explanation:

f(x)= 2x^2 - 3

Plug in x = -3 into the function

f(-3) = 2(-3)^2 - 3

f(-3) = 18 - 3

f(-3) = 15

3 0
3 years ago
Read 2 more answers
Choosing a bicycle with or without shock absorbers with or without lights and 5 color choices
VLD [36.1K]

Answer:with shock absorbers with light red yellow black grey orange

Step-by-step explanation:please give brainliest

5 0
2 years ago
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