3 years ago

T=0.63s +78 can be used to determine T the temp

Mathematics

1 answer:

ruslelena [56]3 years ago

8 0

Answer:

:87997

Step-by-step explanation:

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If 5 adult movie tickets cost $25, how much do 11 tickets cost?

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Answer:

$55

Step-by-step explanation:

5 tickets = $25

1 ticket = $5 (divide by 5 on both sides)

multiply by 11

11 tickets = 5 ×11

11 tickets = $55

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Read 2 more answers

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

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3 years ago