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weeeeeb [17]
2 years ago
14

Which of these parts of a computer produces an observable result?

Mathematics
2 answers:
Olenka [21]2 years ago
7 0

Answer:

c

Step-by-step explanation:

HACTEHA [7]2 years ago
4 0

Answer:

Storage?

Step-by-step explanation:

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Can someone help me with this one i am confused
RideAnS [48]

Answer:

Formula: (x^2 -h) +(y^2 -k)=r^2

The number on the right side of the = is the radius of the circle squared.

(h,k) is the center of the circle.

4 0
3 years ago
Find the midpoint M of the line segment joining the points S = (-8, 3) and T = (2, -1).
Alex

Step-by-step explanation:

use the midpoint formula

( \frac{xs + xt}{2} \:  \:  \frac{ys + yt}{2} )

substitute into the midpoint formula

( \frac{ - 8 + 2}{2}  \:  \:   \frac{3 + ( - 1)}{2} )

solve the above

(

(3 \:  \: 1)

so the x coordinate if your midpoint is 3

the y coordinate of your midpoint is 1

(3;1)

6 0
2 years ago
What is the scaled factor of s to l triangle
ad-work [718]

Answer:

divide 40 by 20

Step-by-step explanation:divideeeeeeee

6 0
2 years ago
Suppose that the grade 7 students expect to sell between 100 and 150 hot dogs how many packages of 12 wieners and 8 buns should
Yuri [45]
15 packs of buns and 10 packs of wieners. 8x15=120 and 12x10=120 so if you make all the hot dogs you will have no buns or hot dogs remaining. I hope this helps you out :)
5 0
2 years ago
When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
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