Question

PLS HELP!! URGENT!!PLS HELP ASAP​

Answer 1

Answer:

a.

perimeter of rectangular = 2 times length + 2 times wide = 2L + 2W = 2 (L + W)

since L is x m and W is y meter, then

perimeter = 2 (L + W) = 2 (x + y)

p = 2(x + y)

(the correct is actually this one

70 ≤ 2(x+y) ≤ 96

b. minimum perimeter

to find minimum perimeter, use the minimum length (which is 20) and minimum wide (which is 15)

p(min) = 2 * ( x(min) + y(min))

p(min) = 2 * (20 + 15)

p(min) = 2 * (35) = 70

c. maximum perimeter

to find maximum perimeter, use the maximum length (which is 30) and maximum wide (which is 18)

p(miax) = 2 * ( x(max) + y(max))

p(max) = 2 * (30 + 18)

p(max) = 2 * (48) = 96 m