Answer:
a.
perimeter of rectangular = 2 times length + 2 times wide = 2L + 2W = 2 (L + W)
since L is x m and W is y meter, then
perimeter = 2 (L + W) = 2 (x + y)
p = 2(x + y)
<em>(the correct is actually this one</em>
<em>70 ≤ 2(x+y) ≤ 96</em>
b. minimum perimeter
to find minimum perimeter, use the minimum length (which is 20) and minimum wide (which is 15)
p(min) = 2 * ( x(min) + y(min))
p(min) = 2 * (20 + 15)
p(min) = 2 * (35) = 70
c. maximum perimeter
to find maximum perimeter, use the maximum length (which is 30) and maximum wide (which is 18)
p(miax) = 2 * ( x(max) + y(max))
p(max) = 2 * (30 + 18)
p(max) = 2 * (48) = 96 m
