Answer:
A
Step-by-step explanation:
The volume of a pyramid is one third the height times the area of the base.
V = ⅓ h A
The base is a square, so the area is the width times length.
V = ⅓ h wl
Problem is, we don't know the height, only the slant length. But we can use this to find the height.
If we cut a cross section down the middle of the pyramid, we get an isosceles triangle. The base of the triangle is 24, and the legs are 37.
If we cut this triangle in half, we get two right triangles. Each right triangle has a base of 12 and a hypotenuse of 37.
Now we can use Pythagorean theorem to find the height of the triangle, which is also the height of the pyramid.
c² = a² + b²
37² = 12² + h²
h = 35
Now we can find the volume. h = 35, w = 24, and l = 24:
V = ⅓ h wl
V = ⅓ (35) (24) (24)
V = 6720
So the volume is 6720 ft³, or answer A.
Answer:
.2
Step-by-step explanation:
when the slope is 7.2 you subtract
Ur answer is c
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![\sqrt{[(6-(-6)]^2+[(2-(-2)]^2} = \sqrt{12^2+4^2} = \sqrt{16} =4 \sqrt{10}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%286-%28-6%29%5D%5E2%2B%5B%282-%28-2%29%5D%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%2B4%5E2%7D%20%3D%20%5Csqrt%7B16%7D%20%3D4%20%5Csqrt%7B10%7D%20)
