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Mrrafil [7]
3 years ago
5

Use a 70% discount coupon or 40%, then 20%, then 10% on your whole purchase?

Mathematics
1 answer:
vredina [299]3 years ago
6 0
It would add up to 70% ?
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What is the factored or of 25y^4 - 4z^2
Cerrena [4.2K]

Answer:

(5y^2+2z)(5y^2-2z)

Step-by-step explanation:

Use the difference of squares formula.

a^2-b^2=(a+b)(a-b)

a=5y^2 \\ b=2z

(5y^2+2z)(5y^2-2z)

5 0
3 years ago
A piece of wire 6 cm long weighs 30 grams. What is the weight of an 8 m length of the same wire?
Feliz [49]

Answer:

4000 gm

Step-by-step explanation:

We can use ratios to solve

Change 8 m to cm

8m * 100cm/1m = 800 cm

6 cm             800 cm

-------------  = ------------

30 grams      x gm

Using cross products

6 * x = 800 * 30

6x = 24000

Divide by 6

6x/6 = 24000/6

x = 4000 gm

5 0
3 years ago
At carl's combine diner, there are three size of coffee drinks regular (300ml), large (500ml) and extra large (800mL), and they
MariettaO [177]

Answer:

The number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

Step-by-step explanation:

Given that the cost for regular coffee drinks (300 ml)=$2.25

The cost for large coffee drinks (500 ml)=$3.25

The cost for extra large coffee drinks (800 ml)=$5.75

Let p,q, and r be the number of regular, large, and extra-large coffee sold.

As the diner sold a total of 37 coffees, so

p+q+r=37

r=37-p-q...(i)

The volume of p regular coffee = 300p ml

The volume of q  large coffee = 500q ml

The volume of r extra-large coffee = 800r ml

As the total volume of coffee sold was 19,100mi, so

300p+500q+800r=19100

By using equation (i)

300p+500q+800(37-p-q)=19100

300p+500q+800 x 37 - 800p - 800q=19100

-500p-300q=19100-29600

500p+300q=10500

500p=10500-300q

p=21-0.6q...(ii)

Now, the cost of p regular coffee=$2.25p

The cost of q large coffee=$3.25q

The cost of r extra-large coffee=$5.75r

As the amount of money made in coffee sales was $133.25, so

2.25p+3.25q+5.75r=133.25

By using equations (1)  we have

2.25p+3.25q+5.75(37-p-q)=133.25

2.25p+3.25q+212.75-5.75p-5.75q=133.25

3.50p+2.50q=79.5

From equation (ii)

3.5(21-0.6q)+2.50q=79.5

73.5-2.1q+2.5q=79.5

0.4q=79.5-73.5=6

q=6/0.4

q=15

From equation (ii)

p=21-0.6(15)

p=12

From equation (i)

r= 37-12-15

r=10

Hence, the number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

5 0
3 years ago
Solve For x Help pleaassee
Mkey [24]

Answer:

x=4

Step-by-step explanation:

C+E=180

14x-8+132=180

14x=180-132+8

14x=56

x=4

6 0
3 years ago
Read 2 more answers
LAST ONE PLEASE HELP. I WILL MARK AS BRAINLIEST.
eimsori [14]

4 in roman numerals is IV. V = 5, and the I is like taking one off the 5. If it was VI, it would be 6, like adding 1. So, IV is 4. The patient will take IV mLs.

5 0
3 years ago
Read 2 more answers
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