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AlexFokin [52]
3 years ago
13

What is... 5. 984 4.761 +670

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0
680.745
get a A.........
Nostrana [21]3 years ago
4 0
680.745 that's easy
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Suppose we want to choose a value of x within 3 units of 11. [This means a value of x that is less than 3 units away from 11.] T
Dahasolnce [82]

Answer:

(a) [8, 14]

(b)  8 \leq x \leq 14

(c)See attachment

Step-by-step explanation:

We want to choose a value of x within 3 units of 11.

(a)Now, 11-3=8 and 11+3=14

The possible values of x ranges is in the closed interval [8,14]

(b) Since x is within 3 units of 11., we have:

|11-x|\leq3

Solving the absolute inequality

-3 \leq 11-x \leq 3\\$In $ -3 \leq 11-x\\ x \leq 11+3\\x \leq 14\\\\$In $ 11-x \leq 3\\ 11-3 \leq x\\8 \leq x\\$Therefore,an inequality that represents all values of x that meet this constraint is:$\\8 \leq x \leq 14

(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.

5 0
3 years ago
Read 2 more answers
If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will
Serhud [2]

Answer:0.75 milligrams will  be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0
3 years ago
Evaluate: |18|<br> A:1/18<br> B:-1/-18<br> C:-18<br> D18
masya89 [10]
Answer will be D. Absolute value can never be negative.
4 0
3 years ago
What is the answer to 5639×824
nikklg [1K]

4,646,536 is the right answer

7 0
3 years ago
Read 2 more answers
Can someone help me
jeka57 [31]
Number one is really easy just set it up in proportions. 420 over x and 7 hours over 24 cause you know there 24 hours in a day and then cross division and simplify. I think.
8 0
3 years ago
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