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maw [93]
3 years ago
15

The rectangular field has a perimeter of 98 meters. The width of the perimeter is three times as much as five times the length.

Calculate the:
a) The length and width of the perimeter.
b) The area of the perimeter.​
Mathematics
1 answer:
White raven [17]3 years ago
4 0

Answer:

a) x = 3.0625m

  y = 45.9375 m

b) A = 140.68359375 m²

Step-by-step explanation:

Let x be the length

Let y be the width

2x + 2y = 98

x + y = 49

y = 3(5x)

y = 15x

x + 15x = 49

16x = 49

x = 3.0625 m

y = 15(3.0625) = 45.9375

A = xy = 3.0625(45.9375) = 140.68359375

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Travis earned $42.50 in 5 h.<br><br> How much will he earn in 8 h at the same rate?
zepelin [54]
Set up a proportion

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4 0
3 years ago
Read 2 more answers
As the number of pages in a photo book increases, the price of the book also increases. There is an additional shipping charge o
wlad13 [49]

Answer:

22

Step-by-step explanation:

Solve the inequality  (20 + 0.5x) + 0.15(20 + 0.5x)   ≤ $62.10 for x:

20 + .5x + 3 + 0.75x ≤ 62.10

Combining the x terms, we get:

20 + 3 + 1.25x ≤ 62.10.

Combining the constants on the left:

23 + 1.75x ≤ 62.10

Combining the constants:

1.75x = 39.10

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Thus, the max number of whole pages she can have in her book is 22.

4 0
3 years ago
The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu
PSYCHO15rus [73]

Answer:

a) I(95,50) = 73.19 degrees

b) I_{T}(95,50) = -7.73

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

a) Calculate I at (T ,H) = (95, 50).

I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19 degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is I_{T}(T,H). So

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H

I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73

8 0
3 years ago
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