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3 years ago

Is the triangle with side lengths of 10 in., 24 in., and 26 in. a right triangle? 85 POINTS

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

Yes, 10 inches on bottom, 24 inches on the side, and 26 inches on the slope. draw it out and it is a right triangle.

monitta3 years ago

5 0

The answer to, Is the Triangle with side lengths of 10 in., 24 in., and 26 in, a right triangle is: Yes. For right triangles, the sum of the squares of the shorter sides is equal to the square of the longer side. Thus, this is a right triangle if 10^2+24^2=26^2. Expanding these squares, we have 100+576=676, which is true. Thus, the triangle is right.

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A 6000-seat theater has tickets for sale at $25 and $40. How many tickets should be sold at each price for a sellout performa

Lena [83]

Step-by-step explanation:

Let x be the amount of tickets sold for $25 and y be the amount of tickets sold for $40, since there are 6000 seats theatre then;

x+y = 6000 .............. 1

If x tickets cost $25 and y tickets are sold for $40 with total revenue of $174,000, then;

25x + 40y = 174,000................ 2

From 1, x = 6000-y ............ 3

Substitute equation 3 into 2:

25x + 40y = 174,000.

25(6000-y) + 40y = 174,000

150,000-25y + 40y = 174,000

150,000+15y = 174,000

15y = 174,000-150,000

15y = 24,000

y = 24,000/15

y = 1600

Substitute y = 1600 into equation 3:

x = 6000-y

x = 6000-1600

x = 4400

<em>Hence 4400 $25 tickets and 1600 $40 tickets must be sold to generate a revenue of $174,000</em>

4 0

3 years ago

A rectangular metal plate is measured to be 7.6cm long and 3.1cm wide, both correct to one decimal place.

ElenaW [278]

Answer:

We know that the rectangular plate has measures of:

length = 7.6 ± 0.05 cm

width = 3.1 ± 0.05 cm

(the error is 0.05cm because we know that both measures are correct to one decimal place)

First, the upper bound of the length is equal to the measure of the length plus the error, this is:

L = 7.6 cm + 0.05 cm = 7.65 cm

The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.

Remember that the area for a rectangle of length L and width W, is:

A = W*L

Then the upper bound of the area is:

A = (7.6cm + 0.05cm)*(3.1cm + 0.05cm) = 10.8 cm^2

5 0

3 years ago

Which one is the missing number? Help please

Readme [11.4K]

The answer is 2.
it’s adding 2 everytime!

5 0

3 years ago

Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.004p=7ln⁡q−3ln⁡p+0.004p=7, where q is

olga2289 [7]

<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:

(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.

So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.

b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:

3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>

8 0

3 years ago

Simplify 3 x + 6 x 2 - 5 x - x 2 .

Anastasy [175]

Pretty sure it’s 5x^2 - 2x

5 0

3 years ago