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deff fn [24]
3 years ago
11

??? Help plz!!!!!!!!!!

Mathematics
2 answers:
marusya05 [52]3 years ago
5 0

Answer:

I'm so sorry

Step-by-step explanation:

you have to re-enter in another format we can't all see the pictures

ASHA 777 [7]3 years ago
3 0

Answer:

runner 3

Step-by-step explanation:

Runner #1 runs 1 mile in 10 minutes

Runner #2 runs 1 mile in 12 minutes

Runner #3 runs 1 mile in 9.5 minutes

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81 cubic feet are in 3 cubic yards.
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100/60 is exactly 1.66666666667. When I do long division my answer comes up as 1.6 with the decimal repeating, am I doing anythi
goblinko [34]

Answer:

I don't think you are doing anything wrong. Just ignore it and write the repeating decimal. If you're asked to do it, round it up instead.

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How do you construct a unique rhombus
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Measurement of one angle and length of one side I think
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A mechanic charges $20.00 an hour, h for labor plus parts. If the parts cost $217.00, write a linear equation that will find the
Dennis_Churaev [7]

Answer:

y=20x+217

Step-by-step explanation:

8 0
2 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
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