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3 years ago

Help me please show work please

Mathematics

1 answer:

harina [27]3 years ago

5 0

Nothing is here I need a question sorry

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Find the slope of a line that is perpendicular to a line that passes through the points (7,1) and (-14,4)

d1i1m1o1n [39]

The slope of the line is -1/7, so the perpendicular line has a slope of 7

7 0

3 years ago

A. -5<br> B. 5<br> C. -2<br> D. 3

Anna71 [15]

Answer:

$\textsf {C. -2}$

Step-by-step explanation:

$\textsf{In the equation y = mx + b, m is the slope and} \\\textsf{b is the value of the y-intercept.}$

$\textsf {The line has a y-intercept at (0, -2), hence b = -2.}$

5 0

2 years ago

Please help. I need to get too 80%

anyanavicka [17]

Answer:

$\frac{3}{500}$

Step-by-step explanation:

Start by converting 5 meters to centimeters. Note 1 meter = 100 centimeters.

We can set up a unit converter:

$5m(\frac{100cm}{1m})$

The meters cancel out leaving us with:

$5*100cm=500cm$

The scale factor is:

$\frac{drawing}{real\ life}=\frac{3cm}{500cm}=\frac{3}{500}$

3 0

3 years ago

Can someone help me I’ll give you that little brain crown thing !!

kati45 [8]

5+4b≥32

7 Packages of bracelets.

Solve It

5+4b≥32

subtract 5 from both sides

4b≥27

divide 4 on both sides

b≥6.75

Since you can't buy a half packet you round up to 7

can I have the brain crown thing

5 0

3 years ago

Read 2 more answers

Travis jogged to his friend's house 10 miles away and then got a ride back home. It took him 2 hours longer to jog there than ri

spin [16.1K]

Using the relation between velocity, distance and time, it is found that his jogging rate was of 4.5 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time,</u> hence:

$v = \frac{d}{t}$

Jogging, his velocity was of v, while the time was of t + 2, for a distance of 10 miles, hence:

$v = \frac{10}{t + 2}$

Riding, his velocity was of 16, while the time was of t, also for a distance of 10 miles, hence:

$v + 16 = \frac{10}{t}$

Then, considering the first equation and replacing in the second:

$\frac{10}{t + 2} + 16 = \frac{10}{t}$

$\frac{10}{t} - \frac{10}{t + 2} = 16$

$\frac{10t + 20 - 10t}{t(t + 2)} = 16$

16t² + 32t - 20 = 0 -> t = 0.5.

Then his jogging rate in mph was:

$v = \frac{10}{0.5 + 2} = 4.5$

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

#SPJ1

8 0

2 years ago