An x or a cross_____________
Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
Answer:
Step-by-step explanation:
square of 15 + square of x = square of 21
225 + square of x = 441
441 - 225 = 216
x = 216
Solve for w:
p = (1.2 w)/h^2
(1.2 w)/h^2 = (6 w)/(5 h^2):
p = (6 w)/(5 h^2)
p = (6 w)/(5 h^2) is equivalent to (6 w)/(5 h^2) = p:
(6 w)/(5 h^2) = p
Multiply both sides by (5 h^2)/6:
Answer: w = (5 h^2 p)/6
