What are the perfect square factors of 3150

(5^49/5^48)+4^0−(1)^79⋅(−3/−4^9)^0

MrMuchimi

Answer:

I believe it is 3.75

Step-by-step explanation:

(5^49/5^48)+4^0−(1)^79⋅(−3/−4^9)^0

5+1−(1)^79⋅(−3/−4^9)^0

5+1−(1)^79

5⋅(−3/−4^9)^0

-3 divided by -4 to the power of 9 to the power of 0=0.75

5 times 0.75=3.75

Hope this is correct! xx

3 0

3 years ago

Over the course of 4 days the price of stock at a corporation fell $28. What was the average change in stock price per day?

bezimeni [28]

7 is the average stock change

5 0

3 years ago

A researcher working in a Human Resources department was interested in gender and sales figures so he conducted a t-test. The me

irina1246 [14]

Answer:

$d = \frac{78.24 -66.25}{\sqrt{\frac{7^2 +7^2}{2}}}= 1.713$

For the interpretation we consider a value for d small is is between 0-0.2, medium if is between 0.2-0.8 and large if is higher than 0.8.

And on this case 1.713>0.8 so we have a large effect size

This value of d=1.713 are telling to us that the two groups differ by 1.713 standard deviation and we will have a significant difference between the two means.

Step-by-step explanation:

Previous concepts

The Effect size is a "quantitative measure of the magnitude of the experimenter effect. "

The Cohen's d effect size is given by the following formula:

$d = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1 +s^2_2}{2}}}$

Solution to the problem

And for this case we can assume:

$\bar X_1 =78.24$ the mean for females

$\bar X_2 =66.25$ the mean for males

$s_1 = s_2= 7$ represent the deviations for both groups

And if we replace we got:

$d = \frac{78.24 -66.25}{\sqrt{\frac{7^2 +7^2}{2}}}= 1.713$

For the interpretation we consider a value for d small is is between 0-0.2, medium if is between 0.2-0.8 and large if is higher than 0.8.

And on this case 1.713>0.8 so we have a large effect size

This value of d=1.713 are telling to us that the two groups differ by 1.713 standard deviation and we will have a significant difference between the two means.

4 0

3 years ago

How many significant digits should the product of 11,435 m and 19.35 m have

DochEvi [55]

Answer:

2 significants choes the least significant digets which is 19.35

result is 221,267.25

6 0

3 years ago

GUYS PLEASE HELP ME I REALLY DON'T UNDERSTAND THIS TASK!!!!!!! IT'S VERY IMPORTANT FOR ME!!!!! DISTANCE BETWEEN TWO TOWNSHIPS, E

Dimas [21]

For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.

5 0

3 years ago