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2 years ago

What is the square root of 7 9/16

Mathematics

2 answers:

Brut [27]2 years ago

8 0

Answer:

2.75

Step-by-step explanation:

So to figure this out, lets start by converting it into a inproper fraction.

So we know that the whole number is 7, and the denominator is 16, so we need to multiply them together to make our fraction improper:

7*16

112

Now add the 9 from what we already had of the fraction:

112+9

121

So our improper fraction is:

121/16

Now we must find the square root.

So to find the square root of a fraction, you have to take the square root of both the numerator and the denominator.

The square root of 121 is 11. We know this because 121 is a perfect square, and 11*11 makes 121.

The square root of 16 is 4. We know this as well because 16 is also a perfect square, and 4*4 makes 16.

So the square root of 121/16 is now:

11/4

If you need to, you can convert this into a mixed fraction or a decimal.

4 goes into 11, 2 times with a remander of 3. So:

2 3/4.

3/4 is equivelent to 0.75, so this can also be:

2.75

This is your answer!

Hope this helps!

Damm [24]2 years ago

6 0

Answer: 11/4

Step-by-step explanation:

Please look into the attachment.

If it was helpful then please make sure to mark it as Brainlist.

Thanks!

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Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

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Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

Find the exact solutions of the system

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

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$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

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$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

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First solution

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

Second solution

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

First solution

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

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2 years ago

What is the square root of 7 9/16​

What is the square root of 7 9/16