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3 years ago

K(x) = 6x+100 k(-5) =

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

Answer:

$k(-5)=70$

Step-by-step explanation:

The given function is

$k(x)=6x+100$

To find k(-5), we put x=-5 into the given function to get;

$k(-5)=6(-5)+100$

Multiply out to obtain;

$k(-5)=-30+100$

This is the same as;

$k(-5)=100-30$

This simplifies to

$k(-5)=70$

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Apples: $(2x) per pound

Ludmilka [50]

Answer:

Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges

Step-by-step explanation:

Cost of one pound of Apple = $2x

Cost of one pound of Grapes = $(6x-5)

Cost of one pound of Oranges = $(x+2)

A shopper purchases one pound each of apples, grapes, and oranges and spends $10.50.

It can be written as: $2x+6x-5+x+2=10.50$

We need to find how much the shopper spend on each fruit.

First we need to find value of x by solving equation

$2x+6x-5+x+2=10.50$

Solving:

$2x+6x+x+2-5=10.50\\9x-3=10.50\\9x=10.50+3\\9x=13.5\\x=\frac{13.5}{9}\\x=1.5$

The value of x is: x=1.5

Now finding cost of one pound each fruit by putting x=1.5

Cost of one pound of Apple = $2x = 2(1.5) = $3

Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4

Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5

So,

Cost of one pound of Apple = $3

Cost of one pound of Grapes = $4

Cost of one pound of Oranges = $3.5

So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges

3 0

3 years ago

If two-thirds of Sam's weekly income is $480, what is one-fourth of his weekly income?

Butoxors [25]

Answer:

180$

Step-by-step explanation:

If two-thirds of Sam's weekly income is $480

so total is $720

720$/4= 180$

3 0

3 years ago

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EXTREMELY URGENT GEOMETRY! 15 POINTS! PLEASE HELP

zhenek [66]

Answer:

20.3 units

Step-by-step explanation:

AB/CB = BD/AB

9/CB = 4/9

CB = 9×9/4

CB = 81/4 = 20¼ units

20.25 (20.3 units correct to 1 dp)

7 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago

Recently, the largest watermelon on record weighed 269 pounds. how many ounces did it weigh?

kirill115 [55]

The watermelon weighed 4,304 ounces.
Important Information:
16 ounces= 1 pound
269 pounds x 16 ounces = 4,304 ounces

3 0

3 years ago

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