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drek231 [11]
3 years ago
6

Find the length of the third side. If necessary, round to the nearest tenth. 17 15

Mathematics
1 answer:
xenn [34]3 years ago
8 0

Answer:

8

Step-by-step explanation:

Use the pythagorean theorem.

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What is the smallest fredholl number that is prime
kaheart [24]
Smallest Fredholl no. that's prime is 13
7 0
3 years ago
Read 2 more answers
If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n
bearhunter [10]

Let x be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is x+4039, so our answer is \boxed{4039}.

For completeness, though, let's solve for the value of x that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term a_1, last term a_n, and n terms, is \frac{n(a_1+a_n)}{2}. Plugging in our known values gives us the equation \frac{4040(2x+4039)}{2}=2020, which simplifies to 2x+4039=1. Thus, x=-2019, so the 4040 consecutive integers are -2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020. Notice how everything except the 2020 cancels out!

4 0
3 years ago
Graph x^3-x^2-2x=0 what are the solutions of the equation
Aleks [24]
X^3 - x^2 - 2x = 0
x ( x^2 - x - 2 ) = 0
x (x-2) (x+1) = 0
x = 0
x-2 = 0 --> x = 2
x+1 = 0 --> x = -1

x = 0, x = 2, x = -1
7 0
2 years ago
How would you calculate the area and perimeter of 3yd 6yd 5yd 10yds
spayn [35]
Okay, start with the smaller square, you know the side length is 3 and that the width is 5, multiply this together:
3 * 5 = 15

That's the smaller left side of this shape, now the bigger side, divide the 10 yards at the bottom by 2 to properly represent the other side then multiply this by the 6 over there.
5 * 6 = 30

Conclusion for Area: After adding the results the answer should be 45.

The perimeter is solely adding all the sides together. You have a 10, two 5's, one 6, and two 3's. Add this together:

10 + 5 + 5 + 6 + 3 + 3 = 32

Conclusion for Perimeter: So the perimeter would be 32.

I hope this helps in someway, have a great rest of your day! ^ ^
| | Ghostgate | |
3 0
3 years ago
A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, ho
Mice21 [21]

Answer:

3.8 seconds

Step-by-step explanation:

Given equation

h= -16t^2 + 60t + 5

When the ball hits the ground then height is 0

So we replace h with 0 and solve for t

0= -16t^2 + 60t + 5

a= -16 , b= 60 and c= 5

Apply quadratic formula to solve for t

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

=\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}

=\frac{-60+-28\sqrt{5}}{-32}

=\frac{4(-15+-7\sqrt{5})}{-32}

=\frac{(-15+-7\sqrt{5})}{-8}

Now make two fractions and solve for x

t= -\frac{7\sqrt{5}-15}{8}=-0.0815

t= \frac{7\sqrt{5}+15}{8}=3.83

So answer is 3.8 seconds


4 0
3 years ago
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