Smallest Fredholl no. that's prime is 13
X^3 - x^2 - 2x = 0
x ( x^2 - x - 2 ) = 0
x (x-2) (x+1) = 0
x = 0
x-2 = 0 --> x = 2
x+1 = 0 --> x = -1
x = 0, x = 2, x = -1
Okay, start with the smaller square, you know the side length is 3 and that the width is 5, multiply this together:
3 * 5 = 15
That's the smaller left side of this shape, now the bigger side, divide the 10 yards at the bottom by 2 to properly represent the other side then multiply this by the 6 over there.
5 * 6 = 30
Conclusion for Area: After adding the results the answer should be 45.
The perimeter is solely adding all the sides together. You have a 10, two 5's, one 6, and two 3's. Add this together:
10 + 5 + 5 + 6 + 3 + 3 = 32
Conclusion for Perimeter: So the perimeter would be 32.
I hope this helps in someway, have a great rest of your day! ^ ^
| | Ghostgate | |
Answer:
3.8 seconds
Step-by-step explanation:
Given equation
When the ball hits the ground then height is 0
So we replace h with 0 and solve for t
a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t
=![\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B-60%2B%5Csqrt%7B60%5E2-4%5Cleft%28-16%5Cright%29%5Ccdot%20%5C%3A5%7D%7D%7B2%5Cleft%28-16%5Cright%29%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5D%3D%5Cfrac%7B-60%2B-%5Csqrt%7B3920%7D%7D%7B-32%7D)
Now make two fractions and solve for x
t= 
=-0.0815
t= 
=3.83
So answer is 3.8 seconds
