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Leokris [45]
4 years ago
9

PLEASE HELP ONLY 2 QUESTION I BEG PLEASE HELP ME :9

Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
5 0
OK so .......


1. A(.2,.-4) , B (.-4,.2) C(0,-.8) all I did was divide each by 1/5


2. A(5,-1) B (1,2) C(-4,-0)




its been like two years since I do this hope I didn't mess up badddd
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25. Willa purchases a vase for her kitchen
IgorC [24]

Answer:

7,7, and 7

Step-by-step explanation:

If she vase is cubical we know that all 3 dimensions are the same. This means that x^3 = 343. So we know the answer is the cube root of 343, which is 7

3 0
3 years ago
Circle A has a diameter of 9 cm Circle B has a radius of 5 cm which Circle has the largest circumference and about how many cent
Alexandra [31]

Answer:

circle b and it is bigger by 1 centimeter

Step-by-step explanation:

since circle b has a radius of 5 and radius is have of the diameter you have to do 5+5 to get the diameter when you do that you get 10 and then you have to subtract circle a diameter which is 9 from circle b diameter which is 10 so 10-9 is 1

4 0
4 years ago
PLZ HURRY!!!! 15 POINTS!
Daniel [21]
I think it’s 7.5 minutes
5 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (1, 1) and (4, 4)?
gizmo_the_mogwai [7]

Answer:

The answer is 1

Step-by-step explanation:

Formula for finding the slope: \frac{y2-y1}{x2-x1}

Take y2 and y1 from (4,<u>4</u>) (1,<u>1</u>)

Take x2 and x1 from (<u>4</u>,4) (<u>1</u>,1)

\frac{y2-y1}{x2-x1}  = \frac{4-1}{4-1} = \frac{3}{3} = 1

This is how the answer is 1

Hope it helps :)

8 0
2 years ago
a ship leave port p and sails on a bearing N50 degree E to Port Q 15km away.then it sails on a bearing of S45 degree E to Port R
Shtirlitz [24]

Answer:

Port r is 100° from Port p and 26km from Port p

Step-by-step explanation:

Lets note the dimension.

From p to q = 15 km = a

From q to r = 20 km= b

Angle at q = 50° + 45°

Angle at q = 95°

Ley the unknown distance be x

Distance from p to r is the unknown.

The formula to be applied is

X²= a²+ b² - 2abcosx

X²= 15² + 20² - 2(15)(20)cos95

X²= 225+400-(-52.29)

X²= 677.29

X= 26.02

X is approximately 26 km

To know it's direction from p

20/sin p = 26/sin 95

Sin p= 20/26 * sin 95

Sin p = 0.7663

P= 50°

So port r is (50+50)° from Port p

And 26 km far from p

3 0
3 years ago
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