Answer:
The correct answer is - option A.
Explanation:
Elephant populations are currently declining lapidary. Human influence is the main and major reason that leads to such a population decline of the elephants. The habitat loss, environmental change, and killing for human safety are the few reasons that affect the population of the elephant, but the major and most responsible cause of the killing and decrease in the elephant population is killing for the ivory of elephants,
Elephant ivory is very expensive and use for making jewelry, artifacts and many more items even illegal medicines are made by ivory.
Thus, the correct answer is option - A.
Answer:
<u> The following four traits are -: </u>
- <u>Pedigree 1 -</u> A recessive trait (autosomal recessive) is expressed by pedigree 1.
- <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
- <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
- <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.
Explanation:
<u>Explaination of each pedigree chart</u>-
- Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected.
In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa) - <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (
) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical
must be contributed by II-6. - The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
- <u>Pedigree 4</u> is an <u>X-linked dominant function</u> characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.
In the question the pedigree chart was missing ,hence it is given below.
Given what we know, we can confirm that in summary, what makes a tunicate more complicated than a sea sponge is cellular differentiation.
<h3>What is cellular differentiation?</h3>
This is what we call the cells ability to specialize itself into a specific cell type. Some examples of this in humans include:
- Heart cells
- Digestive cells
- Reproductive cells
Due to this, tunicates have evolved different tissues, organs, and complete cell types, making them much more complicated organisms than sea sponges.
Therefore, we can confirm that due to the multiple tissues, organs, and systems developed through cellular differentiation, tunicates have become more complicated than sea sponges.
To learn more about cells visit:
brainly.com/question/5763151?referrer=searchResults
B white blood cells function as your immune systems body guards. Osmosis Jones is a great movie to watch in order to learn more about it :)
Answer:
aceptable value is directly accessed where as experimental value is not coinfermed.