Answer:
The percentage of volume taken by iron(II) in the blood cell is 0.0019%.
Explanation:
Radius of iron(II) ions ,r= 75.1 pm =
1 pm = 10^{-6} μm
Volume of sphere =
Volume of single iron(II) ion = V
Number of iron(II) ions in one hemoglobin structure = 4
Number of hemoglobin structure in blood cell = 
molecules
Then number of iron (II) ions in molecules of hemoglobin:
Volume of 
ions of iron = 
Volume of the hemoglobin structure,V' = 
Percentage volume of iron (II) ions in a single blood cell:
=
Answer:
What you'll need:
Milk, snow, vanilla, salt, and sugar
You will also need the following kitchen supplies: a large mixing bowl, a medium mixing bowl, a whisk, and a spoon
Whisk to combine sugar, milk, vanilla extract, and salt.
Add 8 cups of snow (fresh clean snow!!!) to a large bowl.
Pour the milk mixture over the snow and stir to combine
Explanation: Hope this helps<3
The descriptive term applied to the type of diene represented by 2,4-hexadiene is conjugated diene.
Dienes are compounds which contains two double bonds. These dienes can be non conjugated or conjugated.
Conjugated diene are those compound which have two double bonds joined by a single σ bond. Conjugated dienes can also be called 1,3-diene. To know if diene is conjugated or non conjugated, sp³ hybridization is to b checked and the number of double bonds and single sigma bond is checked.
Conjugated dienes are found in many different molecules. 2,4-hexadiene is a conjugated diene with two carbon-carbon double bonds that are separated by one sigma bond.
The stabilization of dienes by conjugation is better than the aromatic stabilization. Conjugated dienes are more stable than non conjugated or cumulative diene because it has higher electron density of molecules delocalized.
To learn more about conjugated dienes,
brainly.com/question/24261651
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Answer:
For this angular momentum, no quantum number exist
Explanation:
From the question we are told that
The magnitude of the angular momentum is 
The generally formula for Orbital angular momentum is mathematically represented as
Where 
is the quantum number
now
We can look at the given angular momentum in this form as
comparing this equation to the generally equation for Orbital angular momentum
We see that there is no quantum number that would satisfy this equation
