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erastova [34]
4 years ago
7

Suppose a student completes an experiment with an average value of 2.9 mL and a calculated standard deviation of 0.71 mL. What i

s the minimum value within a 1 SD range of the average
Chemistry
1 answer:
Makovka662 [10]4 years ago
5 0

Answer:

The correct answer is 2.2 mL.

Explanation:

Given:

Average: 2.9 mL

SD: 0.71 mL

We can define a 1 SD range in which the value of volume (in mL) will be comprised:

Volume (mL) = Average ± SD = (2.9 ± 0.7) mL

Maximum value= Average + SD= 2.9 + 0.7 mL = 3.6 mL

Minimum value= Average - SD = 2.9 - 0.7 mL = 2.2 mL

Thus, the minimum value within a 1 SD range of the average is 2.2 mL

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Perform the following mathematical operation and express the results to the correct number of significant figures. (0.102 x 0.08
Kobotan [32]

Answer:

<u>2.26 </u>

<u></u>

Explanation:

First you should know what are significant figures,

1 . All non - zero digits are significant.

2 . The zero between two non-  zero are significant.Ex 302 has 3 significant figures.

3. The zero before the decimal and before any non-zero digit is non significant. Example : 0.003 has only 1 significant figure.

4. The zero after non zero are non - significant . But the zeros after the decimal point are significant.

300 has only 1 significant figure

300.0 has 4 significant figure

The least number of significant figures present in the number should be there in the final answer of the calculation.

Look at the number having minimum significant digits :

It is 3 (every number has 3- significant figures ) So the answer should also contain 3 - significant figures.

\frac{0.102\times 0.0821\times 273}{1.01}

First solve the numerator part

\frac{2.285}{1.01}

=2.2635

Round off this number to 3 significant figures.

Answer is =<u> 2.26</u>

It has 3 - significant digit since all the digits are non-zero.

5 0
3 years ago
How do the hydrosphere and atmosphere interact? give an example
vladimir1956 [14]

Answer:

Evaporation

Explanation:

Water in the ocean, rivers, lakes, etc. is part of the hydrosphere, and when that water evaporates it enters the atmosphere

3 0
3 years ago
What elements would likely form an ionic bond?
Nutka1998 [239]

Answer:

b. Mg & Cl

a. transferred

46

Explanation:

Ionic bonds form between metals and non-metals when electrons are transferred from one specie to another.

  • The electrostatic attraction from the resulting ions forms the ionic bonds.
  • A metal is electropositive and will readily donate electrons
  • A non-metal is electronegative and will accept electrons.
  • This creates two oppositely charge ions that attracts by means of ionic bonding.

Since Mg and Cl are the only metal - non-metal pair, and ionic bond will form between them.

2.

  In the specie;

          ₄₇Ag¹⁺

47 is the atomic number of the element Ag.

The atomic number is the number of protons in an atom. For a specie in neutral state, the number of protons and electrons are the same.

  • When an atom loses electron, it becomes positively charged.
  • Here Ag has lost one electron and then, the number of electrons becomes 46.
  • The number of protons is still 47
8 0
3 years ago
CAN SOMEONE PLEASE HELP ME ASAP?!!!!
krok68 [10]
A and d is physical, b and c is chemical
4 0
3 years ago
Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are
pantera1 [17]

Answer:

1. Options A and B

2. Options B and C

3.. B. Net ∆G = -16.7 KJ/mol; C. Net ∆G = -14.2 KJ/mol

Explanation:

1. The spontaneity of a chemical reaction depends on its standard free energy change, ∆G. If ∆G is negative, the reaction is favourable, but when it is positive, the reaction is unfavorable.

Therefore, since reaction A and B have ∆G to be positive, they are unfavorable

2. Coupling an unfavorable reaction to a favourable reaction can help the reaction to proceed in the forward direction as long as the net free energy change is negative.

Coupling reaction A and C, as well as reaction B and C will make the reactions to become favourable as net ∆G is negative in both instances.

3. A and C: net ∆G = 13.8 - 30.5 = -16.7 KJ/mol

B and C: net ∆G = 16.3- 30.5 = -14.2 KJ/mol

4 0
3 years ago
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