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jekas [21]
3 years ago
5

___ ___ ___ ___ ___ P ___ ___ ___ ___ ___ ___ ___ mediums allow light to pass through

Chemistry
1 answer:
koban [17]3 years ago
5 0

Answer:

I thought the answer was " T R A N S P A R E N T " but I don't know what the extra two letters are! I'm sorry, that's all I've got..

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Easy one! giving brainly if correct​
Dafna1 [17]

Answer: glass is not considered as solute.

Extra's:

A solute is a substance that gets dissolved in a solvent. ... The solutes in air are oxygen, argon, and carbon dioxide gas, as well as water vapour.

Sugar is a solute in the solvent water. Sugar is one of the most soluble solutes in water.

Also solute is a powder that can be dissolved in solvent like water. here baking soda is a solute.

5 0
3 years ago
You need to produce a buffer solution that has a pH of 5.26. You already have a solution that contains 10. mmol (millimoles) of
Andreas93 [3]

The question is incomplete, complete question is :

You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.

Answer:

33.11 millimoles of acetate we will need to add to this solution.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

Where :

tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid

[salt] = Concentration of salt

[Acid] = Concentration of salt

We have:

pH = 5.26

pK_a=4.74

[salt] =[CH_3COO^-] = ?

[acid] = [CH_3COOH]=10.0 mmol

5.26=4.74+\log(\frac{[CH_3COO^-]}{[10.0 mmol]})

[CH_3COO^-]=33.11 mmol

33.11 millimoles of acetate we will need to add to this solution.

3 0
4 years ago
What is the pOH of the solution?
bagirrra123 [75]

Answer:

The pOH of a solution is the negative logarithm of the hydroxide-ion concentration. The pH of a solution can be related to the pOH.

I looked it up, so idk if it is right...

6 0
3 years ago
Please help me with this question. I don’t understand how to do it
klasskru [66]
Use the Keq equation.. concentraion of products divided by concentration of reactants at equilibrium. (with coefficients as exponents, none in this case reaction is balanced)

Keq = [PCl5] / ([PCl3] [Cl2])

fill in given values and solve for [Cl2] using algebra. Im just going to sub in "c" for the unknown.

0.00094 = 0.44 / 0.33c
0.0003102c = 0.44
c = 1418.44 mol/L
5 0
3 years ago
True or false: The higher the concentration of a substance in a chemical reaction, the faster the reaction rate will be
xenn [34]

Answer:

true

Explanation:

It's true man..............true.........

5 0
3 years ago
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