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Ronch [10]
3 years ago
5

Predict how many antacid tablets it would take to produce 120 mL of CO2 gas

Chemistry
1 answer:
Alja [10]3 years ago
7 0
<span>The question does not mention the brand or size of antacid tablets, but some research in the internet shows that for a very common brand, Alka Seltzer, that it takes about 4 tablets to produces 60 mL of gas. So for 120mL it will take 120/60 x 4 or 8 tablets to produce 120 mL of CO2 gas.</span>
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Which of the following is not present in an atom?<br> Electron<br> Element<br> Neutron<br> Proton
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Answer:

an element is not in an atom

Explanation:

because the only things in a atom are electrons neutrons and protons

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Answer:

A concentrated acid is an acid which is in either pure form or has a high concentration. Laboratory type sulfuric acid (about 98% by weight) is a concentrated (and strong) acid. A dilute acid is that in which the concentration of the water mixed in the acid is higher than the concentration of the acid itself.

Explanation:

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Chloroform flows through a 4.26 inch inside-diameter pipe at the rate of 3.60 gallons per minute. What is the average velocity o
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Answer:

1) 0,081 ft/s

2) 0,746 lb/s

Explanation:

The relation between flow and velocity of a fluid is given by:

Q=Av

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  • A, cross section of the pipe [ft2]
  • v, velocity of the fluid [ft/s]

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To convert our data to appropiate units, we use the following convertion factors:

1 ft=12 inches

1 ft3=7,48 gallons

1 minute=60 seconds

So,

Q=\frac{3,60 gallons}{1 min}*\frac{1min}{60 s}*\frac{1ft3}{7,48gallons}=0,00802 \frac{ft3}{s}

As the pipe has a circular section, we use A=πd^2/4:

d=4,26 inch *\frac{1ft}{12 inch}=0,355ft\\  A=\pi \frac{0,355^{2} }{4}=0,0989ft2

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Q=vA......................v=Q/A

v=\frac{0,00802ft^{3} /s}{0,0989ft^{2} }=0,081ft/s

2)

The following formula is used to calculate the specific gravity of a material:

SG = ρ / ρW  

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ρ = SG*ρW   = 1,49* 62,4 lb/ft3 = 93 lb/ft3

To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume:

0,00802 \frac{ft3}{s}*\frac{93lb}{1ft3}=0,746lb/s

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