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goblinko [34]
3 years ago
12

If an item is on sale for 10% off and you know you will need to pay a 10% tax, will the final price of the item be less than, gr

eater than, or equal to the original price? Explain.
Mathematics
2 answers:
balandron [24]3 years ago
8 0

Answer:

The price is equal

Step-by-step explanation:

10%-10% =0

sp2606 [1]3 years ago
3 0
The answer would be eaqual to
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ZXCVBNM<>?a soasnv sao vvnv anisovanv avniavnao
Margarita [4]

Answer:

???

Step-by-step explanation:

8 0
3 years ago
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jenna is running a trail that is 8 and 4/7 miles long. if she finished 5/9 of the distance about how far has she run?
Julli [10]
Trail is 8 and 4/7
she ran 4/7 of it


convert 8 and 4/7 to improper for ease
8 and 4/7=8+4/7=56/7+4/7=60/7
4/7 of 60/7=
4/7 times 60/7=
240/49=
196/49+44/49=
4 and 44/49

she ran 4 and 44/49 miles



3 0
3 years ago
Helppppp !!!!!! <br><br>5a + ( -5 ) - 3a + 10b - 3 - b = ?​
AlekseyPX
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5a + ( -5 ) - 3a + 10b - 3 - b

( 5a - 3a ) + ( -5 - 3 ) + ( 10b - b )

2a + ( -8 ) + 9b

◇◆□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□◆◇

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3 0
3 years ago
Read 2 more answers
How can I reflect this horizontally without a value for h?
Alex_Xolod [135]

Answer:

Another transformation that can be applied to a function is a reflection over the x– or y-axis. A vertical reflection reflects a graph vertically across the x-axis, while a horizontal reflection reflects a graph horizontally across the y-axis. The reflections are shown in Figure 9.

Graph of the vertical and horizontal reflection of a function.

Figure 9. Vertical and horizontal reflections of a function.

Notice that the vertical reflection produces a new graph that is a mirror image of the base or original graph about the x-axis. The horizontal reflection produces a new graph that is a mirror image of the base or original graph about the y-axis.

A GENERAL NOTE: REFLECTIONS

Given a function \displaystyle f\left(x\right)f(x), a new function \displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x) is a vertical reflection of the function \displaystyle f\left(x\right)f(x), sometimes called a reflection about (or over, or through) the x-axis.

Given a function \displaystyle f\left(x\right)f(x), a new function \displaystyle g\left(x\right)=f\left(-x\right)g(x)=f(−x) is a horizontal reflection of the function \displaystyle f\left(x\right)f(x), sometimes called a reflection about the y-axis.

HOW TO: GIVEN A FUNCTION, REFLECT THE GRAPH BOTH VERTICALLY AND HORIZONTALLY.

Multiply all outputs by –1 for a vertical reflection. The new graph is a reflection of the original graph about the x-axis.

Multiply all inputs by –1 for a horizontal reflection. The new graph is a reflection of the original graph about the y-axis.

EXAMPLE 7: REFLECTING A GRAPH HORIZONTALLY AND VERTICALLY

Reflect the graph of \displaystyle s\left(t\right)=\sqrt{t}s(t)=√

t

(a) vertically and (b) horizontally.

SOLUTION

a. Reflecting the graph vertically means that each output value will be reflected over the horizontal t-axis as shown in Figure 10.

Graph of the vertical reflection of the square root function.

Figure 10. Vertical reflection of the square root function

Because each output value is the opposite of the original output value, we can write

\displaystyle V\left(t\right)=-s\left(t\right)\text{ or }V\left(t\right)=-\sqrt{t}V(t)=−s(t) or V(t)=−√

t

Notice that this is an outside change, or vertical shift, that affects the output \displaystyle s\left(t\right)s(t) values, so the negative sign belongs outside of the function.

b.

Reflecting horizontally means that each input value will be reflected over the vertical axis as shown in Figure 11.

Graph of the horizontal reflection of the square root function.

Figure 11. Horizontal reflection of the square root function

Because each input value is the opposite of the original input value, we can write

\displaystyle H\left(t\right)=s\left(-t\right)\text{ or }H\left(t\right)=\sqrt{-t}H(t)=s(−t) or H(t)=√

−t

Notice that this is an inside change or horizontal change that affects the input values, so the negative sign is on the inside of the function.

Note that these transformations can affect the domain and range of the functions. While the original square root function has domain \displaystyle \left[0,\infty \right)[0,∞) and range \displaystyle \left[0,\infty \right)[0,∞), the vertical reflection gives the \displaystyle V\left(t\right)V(t) function the range \displaystyle \left(-\infty ,0\right](−∞,0] and the horizontal reflection gives the \displaystyle H\left(t\right)H(t) function the domain \displaystyle \left(-\infty ,0\right](−∞,0].

TRY IT 2

Reflect the graph of \displaystyle f\left(x\right)=|x - 1|f(x)=∣x−1∣ (a) vertically and (b) horizontally.

Solution

EXAMPLE 8: REFLECTING A TABULAR FUNCTION HORIZONTALLY AND VERTICALLY

A function \displaystyle f\left(x\right)f(x) is given. Create a table for the functions below.

\displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x)

\displaystyle h\left(x\right)=f\left(-x\right)h(x)=f(−x)

\displaystyle xx 2 4 6 8

\displaystyle f\left(x\right)f(x) 1 3 7 11

SOLUTION

For \displaystyle g\left(x\right)g(x), the negative sign outside the function indicates a vertical reflection, so the x-values stay the same and each output value will be the opposite of the original output value.

\displaystyle xx 2 4 6 8

\displaystyle g\left(x\right)g(x) –1 –3 –7 –11

For \displaystyle h\left(x\right)h(x), the negative sign inside the function indicates a horizontal reflection, so each input value will be the opposite of the original input value and the \displaystyle h\left(x\right)h(x) values stay the same as the \displaystyle f\left(x\right)f(x) values.

\displaystyle xx −2 −4 −6 −8

\displaystyle h\left(x\right)h(x) 1 3 7 11

TRY IT 3

\displaystyle xx −2 0 2 4

\displaystyle f\left(x\right)f(x) 5 10 15 20

Using the function \displaystyle f\left(x\right)f(x) given in the table above, create a table for the functions below.

a. \displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x)

b. \displaystyle h\left(x\right)=f\left(-x\right)h(x)=f(−x)

3 0
2 years ago
A ball is dropped straight down from a height of 200 feet. After 1 second? The hall is 184 feet above the ground. After 2 second
mote1985 [20]

The motion of the ball dropped from height is a free fall motion due to

gravitational acceleration.

<h3>Correct response;</h3>
  • The equation that models the height is; <u>y = -16·x²</u>

<h3>Method for arriving at the above equation;</h3><h3>Given values;</h3>

\begin{tabular}{|c|c|}Height (feet)&Time (s)\\200&0\\184&1\\136&2\end{array}\right]

<h3>Required:</h3>

To select the equation that models the height, <em>y</em>, of the ball <em>x</em> seconds after

its dropped;

<h3>Solution:</h3>

From the above table, we have that the first difference is not a constant

The second difference is = 48 - 16 = 32

Taking the second difference as a constant, we have the following

quadratic sequence;

y = a·x²  + b·x + c

Where;

x = The time in seconds

y = The height after <em>x</em> seconds

  • At x = 0, we have;

200 = a·0² + b × 0 + c

Therefore;

c = 0

  • At<em> x</em> = 1, we have;

184 = a × 1² + b × 1 + 200

184 = a + b + 200

a + b = -16

a = -16 - b

  • At <em>x</em> = 2, we have;

136 = a × 2² + b × 2 + 200

136 = 4·a + 2·b + 200

-64 = 4·a + 2×b

Therefore;

-64 = 4 × (-16 - b) + 2×b

-64 = -64 - 4·b + 2×b

b = 0

a + b = -16

Therefore;

a + 0 = -16

a = -16

The equation that models the height is; y = <u>-16·x²</u>

Learn more about quadratic function here;

brainly.com/question/2293136

4 0
2 years ago
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