After putting the value of y from the second equation to the first equation, the resultant equation is 
.
GIven:
The equations are:
It is required to put the value of y from second equation to the first equation.
<h3>How to solve equations?</h3>
The value of y from the second equation is,
Now, put this value of y in the first equation as,
Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is .
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Answer - 4 classes
117 ÷ 29 = 4.03...
That is the answer. hope this helps.
Answer:
(f + g)(x) = 12x² + 16x + 9 ⇒ 3rd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- We can add and subtract two function by adding and subtracting their
like terms
Ex: If f(x) = 2x + 3 and g(x) = 5 - 7x, then
(f + g)(x) = 2x + 3 + 5 - 7x = 8 - 5x
(f - g)(x) = 2x + 3 - (5 - 7x) = 2x + 3 - 5 + 7x = 9x - 2
* Lets solve the problem
∵ f(x) = 12x² + 7x + 2
∵ g(x) = 9x + 7
- To find (f + g)(x) add their like terms
∴ (f + g)(x) = (12x² + 7x + 2) + (9x + 7)
∵ 7x and 9x are like terms
∵ 2 and 7 are like terms
∴ (f + g)(x) = 12x² + (7x + 9x) + (2 + 7)
∴ (f + g)(x) = 12x² + 16x + 9
* (f + g)(x) = 12x² + 16x + 9
Inflection at f'(x) = 0
<span>
x^1/2 / (1 + x + x^3) = 0 </span>
<span>The x coordinate is x = 0 </span>
<span>
or "C" from your choices there. </span>
<span>The simplest way is to notice that this happens when x = 0. The reason is you got: </span>
<span>
x^1/2 / (some expression) </span>
<span>
at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. </span>
<span>
The denominator for x = 0 is 1 so you get </span>
<span>
0/1 = 0.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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