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2 years ago

What is the length (magnitude) of the vector (7,-2)?

Mathematics

1 answer:

Ulleksa [173]2 years ago

7 0

Answer:

d. sqrt 53

Step-by-step explanation:

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A dolphin jumps from the water at initial velocity of 16 feet per second. The equation h= -16t^2+80t models the dolphin's height

Travka [436]

Answer:

d) 100 feet

Step-by-step explanation:

The x value of the vertex (highest point in this case) is found via -b/2a:

-80/-32 = 2.5

Plug 2.5 into the function:

h(2.5) = -16(2.5)² + 80(2.5)

= - 100 + 200 = 100

7 0

2 years ago

Find the discriminant, and determine the number of real solutions. then solve x^2 +8x+20=0

vodomira [7]

Answer:

Part 1) The quadratic equation has zero real solutions

Part 2) The solutions are

$x_1=-4+2i$ and $x_2=-4-2i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}+8x+20=0$

$a=1\\b=8\\c=20$

The discriminant is equal to

$D=(b^{2}-4ac)$

If D=0 -----> the quadratic equation has only one real solution

If D>0 -----> the quadratic equation has two real solutions

If D<0 -----> the quadratic equation has two complex solutions

<em>Find the value of D</em>

$D=8^{2}-4(1)(20)=-16$ -----> the quadratic equation has two complex solutions

<em>Find out the solutions</em>

substitute the values of a,b and c in the formula

$x=\frac{-8(+/-)\sqrt{8^{2}-4(1)(20)}} {2(1)}$

$x=\frac{-8(+/-)\sqrt{-16}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{-8(+/-)4i} {2}$

$x_1=\frac{-8(+)4i} {2}=-4+2i$

$x_2=\frac{-8(-)4i} {2}=-4-2i$

8 0

3 years ago

Is 5 degrees above zero a negative quantity always never or sometimes

7nadin3 [17]

Answer:

never

Step-by-step explanation:

5 degrees above zero is never a negative, it's positive

5 0

2 years ago

PLEASE HELP IM CONFUSED

jeka57 [31]

Answer:

178° 35'

Step-by-step explanation:

∠ACB and ∠ACD are supplementary, so they add up to 180°.

First, convert to degrees (there are 60 minutes in a degree).

∠ACB = 1°25' = 1° + (25/60)° = 1.4167°

Now find the supplementary:

∠ACD = 180° − 1.4167°

∠ACD = 178.5833°

∠ACD = 178° 35'

8 0

3 years ago

Which is the solution to the inequality? y minus 27 greater-than-or-equal-to negative 13 y greater-than-or-equal to negative 40

djyliett [7]

Answer:

$y\geq 14$

y greater than or equal to 14

Step-by-step explanation:

Given the inequality:

$y-27\geq -13$

We solve it by isolating the variable y on one side. That is, in our case we add 27 to both sides and get:

$y-27\geq -13\\y\geq 27-13\\y\geq 14$

3 0

2 years ago

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