First, let's work out the denominator. 5^ -2 = 1/25. When an exponent is negative, it means to put a 1 over the product. Like we did earlier.
Now we have 1 / (1/25).
1 / (1/25) Divide 1 by 25. 1 / 0.04 Divide 1 by 0.04 25
The answer is 25!
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We have two points so we can find the gradient using y1-y2/x1-x2 gradient = 21-27/2-8 = 1 we know the form for any linear equation is y = mx + c we have m and a point so we can substitute in point (2,21) to find c 21 = 1 x 2 + c c = 19 therefore, the equation is y = x + 19