Answer:
The answer to your question is: ![\sqrt[4]{2^{3} } + 1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E%7B3%7D%20%7D%20%2B%201)
Step-by-step explanation:
![\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B2-%201%7D%7D%20%20x%20%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%20%2B%201%7D%20%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%5Btex%5D%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B2%20-%201%7D)
=
X - y = 5
x = y + 5
y = x - 5
Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
Use a system of inequalitiesto modelthe scenario above so the correct answer is letter A
Answer:
The second one is correct.
