Step-by-step explanation:
what is the problem ? what needs to be done ?
all that you are showing here is the definition of a number range.
it means all numbers, for which 1.3 is smaller or equal.
in short, all numbers that are greater or equal to 1.3.
Answer:
y= 1/3 x +5
Step-by-step explanation:
To find the slope, we take two points
(0,5) and (15,10)
The slope is found by the formula
m = (y2-y1)/ (x2-x1)
= (10-5)/(15-0)
= 5/15
= 1/3
The slope is 1/3
The y intercept is found when x=0
When x=0 y=5
The slope intercept form of the line is
y=mx+b where m is the slope and b is the y intercept
y= 1/3 x +5
Ok so,
20*2= 40
20*1/2=10
40+10=50
So Johncan travel 50 km in 2 1/2 hours.
Hope this helps :)
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
