Answer:
Step-by-step explanation:
a) It can be convenient to use the square root function as one being defined only for values greater than or equal to some number. Here, we need to shift that function 3 units to the left, so its domain is [-3, ∞).
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b) One way to put holes in a function is to put vertical asymptotes there. This function can be defined to have vertical asymptotes at x=2 and x=4 so those values are excluded from the domain.
Answer:
Step-by-step explanation:
first problem:
3 is a solution to x^2=9, so to a, b, c and d
second problem
-2 is a solution to:
a, b, c and d because (-2)^2=4, 4=4, b) 5*(-2)^2=5*4=20 and so on
basically to all choices
the third, solve the equations:
x^2=1, =
, x=1
x^2=81 sqrtx^2=sqrt81, x=+and -9
4x^2=1 divide by 4 , x^2=1/4, x=+&- 1/2 (plus si minus 1/2, amindoua solutiile sint valabile)
3x^2=75, we divide by 3, we get x^2=25, x=+&-5
49x^2=121 , x=+and- 11/7
25x^2=225 divide by 25, x^2=9, x =+and - 3
36x^2=144 we divide by 36, we get x^2=4, x = +and- 2
x^2-0.25=0 x^2=0.25, x=+and - 1/2
2x^2-0.32=0 , 2x^2=0.32, x^2=0.16 ( i divided by 2) , x=+and- 2/5
4x^2=0.04, divide by 4, x^2=0.01, x=+and - 0.1
3x^2=10.8, divide by 3, x^2=3.6, x=+and - 1,89
for the : determinati solutiile ecuatiilor
a) (x-1)^2=49, do the quadratic, you get x=8 and -6
due to the length of this page, i cant explain every step
b) (2x+1)^2=81, you get x= 4 and -5
c)(3x-1)^2=121, do the quadratic, x=- 10/3 and +4
d) 3(x-3)^2=48, we divide by 3 first , (x-3)^2=16, we get x=7 and -1
e)5(x+2)^2=45 we divide by 5, (x+2)^2=9, x=+1and -5
f) 7(2x-1)^2=175 we divide by 7 and we have (2x-1)^2=25 x=+3 and -2
Determine x belong to R
a) 1/9 x^2=16, we multiply 9*16=144, x^2=144, x=+and - 12
1/100x^2-1/64=0, or 1/100 x^2=1/64, x=+and - 5/4
1/25 x^2=0.49, x^2=0.49*25=12.25, x=+ and - 7/2
