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Wewaii [24]
3 years ago
9

I don’t know technically

Computers and Technology
2 answers:
butalik [34]3 years ago
8 0
The answer would be d
gregori [183]3 years ago
3 0
I go to that school to and it would be d I think I'm not sure
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frosja888 [35]

Answer:

1000 megabytes are in a gigabyte

Explanation:

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While moving into a new apartment, Titus needed to hold the door open with something heavy. It suddenly dawned on him that he co
tiny-mole [99]

Answer:probably and solution

Explanation:

7 0
3 years ago
A customer has a new laptop with wireless WAN capabilities; however, the software does not connect to the Internet. What would y
LUCKY_DIMON [66]

Answer:

Check below for the explanation

Explanation:

The following suggestions will be given to the customers:

  • Go to network settings and check the WIFI settings to confirm whether the WIFI connection is on. Switch the WIFI to the on position if it is off.
  • The customer should check if the wireless driver is installed on the computer, if the driver is not installed, he should try to install it
  • The customer should check all the available access points and confirm if their signal strengths are strong enough to allow for any connections. Restart the access point to enhance proper connection.
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  • Run a Network Diagnostics on your computer. This will run a couple of tests to see what’s possibly causing your Wi-Fi issues.
5 0
4 years ago
Given input characters for an arrowhead and arrow body, print a right-facing arrow. Ex: If the input is: *
MrRa [10]

Answer:

Following are the code to this question:

b= input()#defining b variable for input character value

h= input()#defining h variable for input character value

b_width=6#defining b_width variable that holds an integer value 6

r1 = ' ' * b_width+h#defining r1 variable that calculates hash lines

r2 = b*b_width+h*2#defining r3 variable that calculates 6 asterisk and 2 hash line  

r3 = b*b_width+h*3#defining r3 variable that calculates 6 asterisk and 3 hash line

print(r1)#print r1 variable value

print(r2)#print r2 variable value

print(r3)#print r3 variable value

print(r2)#print r2 variable value

print(r1)#print r1 variable value

Output:

please find the attachment.

Explanation:

In the given python code, three variable "b,h, and b_width" is declared, in which "b_width" holds an integer variable "6" and variable "b and h" is used to an input character value.  In the next line, "r1, r2, and r3" is declared, that holds arrowhead values which can be defined as follows:

  • In the "r1" variable, it stores space with b_width variable and one h variable value.
  • In the "r2" variable it stores b_width and 2*h variable value.
  • In the "r3" variable it stores b_width and 3*h variable value.

At the last, it prints the "r1, r2, and r3" variable value and for arrowheads,  it follows the above program code.

6 0
3 years ago
Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw
erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

  • Use the built-in rand function to generate a random coin.
  • Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
  • Check if the coins give a value of temp, then answer is correct and the values of user will be added.
  • Optimum solution is displayed  If it does not matches with the optimum solution. Display that the answer is wrong along with solution.
6 0
3 years ago
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