Answer:
A is the answer 456% and 512%
Step-by-step explanation:
Percent Errors
Trial A
Trial B
Measured Value
240
195
Actual Value
200
240
Percent Error
?
?
Complete the table.
Percent Errors
Trial A
Trial B
Measured Value
240
195
Actual Value
200
240
Percent Error
440440%
435435%
Answer:
The standard deviation of weight for this species of cockroaches is 4.62.
Step-by-step explanation:
Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
To find : What is the approximate standard deviation of weight for this species of cockroaches?
Solution :
We have given,
Mean 
The sample mean x=55
A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
i.e. P(X>55)=14%=0.14
The total probability needs to sum up to 1,



The z-score value of 0.86 using z-score table is z=1.08.
Applying z-score formula,

Where,
is standard deviation
Substitute the values,





The standard deviation of weight for this species of cockroaches is 4.62.
There you go please brainliest thanks!
Answer:
-333
Step-by-step explanation:
It seems like it is going down by -30 each term.
The function is stretched vertically by a factor of 3.
The function shifts 2 to the right.
The function is moved 5 units up.
Explanation:
The parent function of the graph is 
The transformation for the parent function is given by 
Thus, the transformed function is in the form of 
where a is the vertical compression/stretch,
h moves graph to left or right and
k moves the graph up or down.
Thus, from the transformed function
, we have,

The attached graph below shows the transformation of the graph that the graph is stretched vertically by a factor of 3 and shifted 2 units to the right and moved 5 units up.
Hence, The function is stretched vertically by a factor of 3.
The function shifts 2 to the right.
The function is moved 5 units up.