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artcher [175]
4 years ago
12

A charity auction to help dogs that need homes raised $526. If the money is evenly split to help 8 dogs, how much

Mathematics
2 answers:
alina1380 [7]4 years ago
4 0

Answer:

Step-by-step explanation: so you would do $526 divided by 8 because there are 8 dogs so you would take to the total number. So the answer would be

65.75

Len [333]4 years ago
4 0

Answer:

$65.75

Step-by-step explanation:

to get the answer you'd take 526 and divide it by 8

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You start at (1,0) And move down 2 units and left 4 units where do you end
djverab [1.8K]

Answer:

(-3,-2)

Step-by-step explanation:

Starting at the point (1, 0)

Now we move don 2 units (so the y-value reduces in two units) making now the point (1,0-2)  which is (1, -2)

then we move to the left 4 units (so the x-value has now to be decreased in 4 units) making the point: (1-4, -2) which is (-3, -2)

3 0
3 years ago
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Planners of an experiment are evaluating the design of a sphere of radius r that is to be filled with helium (0°c, 1 atm pressur
Vikentia [17]
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3 
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3 
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3) 
The density of silver is 10.5g/cm^3 
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2) 

Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3 

Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2) 
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
6 0
3 years ago
Have the conditions for inference been met?
alekssr [168]

Answer: the answer is A

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youre welcome

5 0
3 years ago
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FromTheMoon [43]
Question 5 is (-3,4)
4 0
2 years ago
The lowest temperature ever recorded at Oymyakon in Russia was 96.2°F below 0°F. The lowest temperature ever recorded at Prospec
Alekssandra [29.7K]

Answer:

Thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F

Thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F

Step-by-step explanation:

If the temperature is x° F below 0° F then the thermometer reading is -x° F

It is given that the Lowest temperature recorded at Oymyakon in Russai was 96.2°F below 0°F

So the thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F

Also it is given that the Lowest temperature recorded at Prospect Creek in Alaska  was 80°F below 0° F

So the thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F

7 0
3 years ago
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