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Mandarinka [93]
3 years ago
10

A customer has a credit card that charges 18% simple interest every year. How much interest will the customer save

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

$900

Step-by-step explanation:

18% of $5000

0.18×5000=900

The customer will save $900

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Ac=4 bx=y+4 what is the value of y
Kitty [74]
Ac=4 bx=y+4 doesn't make sense.  Perhaps you meant <span>Ac-4bx=y+4.  If this is not correct, ensure that you have copied down the original problem correctly.

</span>To solve  Ac-4bx=y+4  for y, subtract 4 from both sides of this equation.  You'll get:

Ac-4bx-4 = y+4 - 4, or y = ac-4bx - 4.
6 0
3 years ago
What is being done to the variable in the equation m/5 = -40?
vredina [299]

Answer:

It's being divided by 5.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Answer for BRAINLIEST!! <br> 2y to the power of 2−y−5=0
Blababa [14]
2² - y - 5 = 0 

Evaluate the power.

4 - y - 5 = 0

Calculate the sum or difference.

-1 - y = 0

Move constant to the right side and change its sign. 

-y = 1

Change the signs on both sides of the equation.

y = -1


4 0
4 years ago
In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older
Viktor [21]

Answer:

p_v =P(t_{(63)}>2.5)=0.0075  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=45 represent the mean height for the sample  

s=16 represent the sample standard deviation for the sample  

n=64 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=64-1=63  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(63)}>2.5)=0.0075  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

6 0
3 years ago
A frog is jumping onto a lily pad. Its height, h (in feet), is recorded at various seconds, t, in the
myrzilka [38]

Answer:

I don't know

Step-by-step explanation:

sorry

7 0
3 years ago
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