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Ne4ueva [31]
3 years ago
12

Let's say you asked how many moles of O2 are needed to react with 24 moles of C2H6.

Chemistry
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

7

Explanation:

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2 years ago
A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
grin007 [14]

Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

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3 years ago
A chemist dissolves 1.3 mol NaCl in a 2.0-kg sample of water. What is the boiling point of this solution? (Assume that pure wate
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ΔT(boiling point)  = (Kb)mi
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T(boiling point) = 100 + 0.67 = 100.67 degrees Celsius</span>
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