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artcher [175]
3 years ago
13

Gram mass formula of glycine

Chemistry
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

75.07 g/mol

Explanation:

75.07 g/mol

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What type of bond is joining the two hydrogen atoms?
Julli [10]
Bonding between 2 hydrogen atoms is 'covalent bond'.

Hope this helps you.
7 0
4 years ago
I need answers plz<br>btw D says ice crystals ​
tangare [24]

Answer:

B. Hydrogen and oxygen molecules

General Formulas and Concepts:

<u>Chemistry - Reactions</u>

  • Reactants are always on the left side of the arrow
  • Products are always on the right side of the arrow

Explanation:

<u>Step 1: Define</u>

Reaction RxN:   2H₂ + O₂ → 2H₂O

<u>Step 2: Identify</u>

Reactants:   H₂ and O₂

Products: H₂O

7 0
3 years ago
In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56
larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

8 0
4 years ago
A student measures the boiling point of water in the lab over three trials and gets the following
maw [93]

I think both are accurate

7 0
3 years ago
Read 2 more answers
Calculate the decrease in temperature (in Celsius) when 2.00L at 21.0*C is compressed to 1.00.
Anna71 [15]

Decrease in temperature is -126.0°C

<u>Explanation:</u>

Using Charles law we can set up the equation as,

V₁/T₁ = V₂/T₂

(2.00 L) / 294.0 K) = (1.00 L) / (x)

cross multiply to get:

2x = 294

2x/2 = 294/2

x = 147.0 K

Now kelvin is converted into Celsius by subtracting 273 from 147 as,

147 - 273 = -126°C

8 0
4 years ago
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