Answer:
A student mixes baking soda and vinegar in a glass. ... Yes I do belive that new substances are being formed because there is a chemical reaction between the baking soda and vinegar turning it into a bubbly substances instead of a powder and liquid.
Explanation:
<span>The substance that is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(I), and molten magnesium iodide, mgi2(I), can be expressed as Ca2+ + 2eâ’ --> Ca. At the anode, the substance can be expressed as 2Brâ’ â’ 2eâ’ --> Br2. At the cathode for magnesium iodide can be expressed as Mg2+ + 2 eâ’ --> Mg, and 2 Iâ’ â’ 2 eâ’ --> I2 at the anode.</span>
Answer: a) pH of a 0.1 M vinegar solution is 2.9
b) It is an acid as pH is less than 7
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.
As vinegar is a weak acid, its dissociation is represented as;
cM 0 0
So dissociation constant will be:
Give c= 0.1 M
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=0.1\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.1%5Ctimes%20%5Calpha)
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![pH=-log[1.3\times 10^{-3}]=2.9](https://tex.z-dn.net/?f=pH%3D-log%5B1.3%5Ctimes%2010%5E%7B-3%7D%5D%3D2.9)
Thus pH of a 0.1 M vinegar solution is 2.9
As pH is less than 7, it is an acid.
A it increases is the correct answer.
Good luck and I hope this helps.!
