Answer:
79 extractions
Explanation:
An<em> isooctane/water partinioning constant</em> of 12/1 means that 12 out of 13 parts of the Pb²⁺ complex will be found in isooctane, while the remaining 1 out of 13 part will remain in water.
- 12/13 * 100 = 92.3% of the Pb²⁺ will be removed with each extraction.
Now we <u>convert 1.4 mg/mL to ug/mL</u>:
- 1.4
= 140 ug/mL
We're looking to have a final concentration of 0.25 ug/mL, so we can write:
- 140 mg/mL * (0.923)ⁿ = 0.25 ug/mL
Where <em>n</em> is the number of extractions.
We <u>solve for </u><u><em>n</em></u>:
- n = ln (1.786x10⁻³) / ln (0.923)
Answer:
A) solubility
B)luster
D)Density
F)magnetism
Explanation:
A physical property is one that tells us everything about what a substance is when no change is is occurring to its constituent.
Such properties can be observed with our senses or instruments or pieces of apparatus.
- Examples are luster, density, solubility, taste, odor, color, melting point, boiling point etc.
I believe that Isotopes of elements have different atomic masses. So A) Atomic masses.
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
