Answer:
0.1938 = 19.38% probability that a package is delivered by UPS if it weighs 2 lbs or more
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: It weighs 2 lbs or more
Event B: Delivered by UPS
15% of the packages that are delivered by UPS weighs 2 lbs or more.
This means that ![P(A \cap B) = 0.15](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%200.15)
More than 2 lbs:
15% of 20%(UPS)
93% of 80%(Not delivered by UPS). So
![P(A) = 0.15*0.2 + 0.93*0.8 = 0.774](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.15%2A0.2%20%2B%200.93%2A0.8%20%3D%200.774)
a. What is the probability that a package is delivered by UPS if it weighs 2 lbs or more
![P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.774} = 0.1938](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D%20%3D%20%5Cfrac%7B0.15%7D%7B0.774%7D%20%3D%200.1938)
0.1938 = 19.38% probability that a package is delivered by UPS if it weighs 2 lbs or more