Using the normal distribution, there is a 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
For this problem, the parameters are given as follows:
The probability is the <u>p-value of Z when X = 16 subtracted by the p-value of Z when X = 15</u>, hence:
X = 16:
By the Central Limit Theorem
Z = 2.11
Z = 2.11 has a p-value of 0.9826.
X = 15:
Z = 0
Z = 0 has a p-value of 0.5.
0.9826 - 0.5 = 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.
More can be learned about the normal distribution at brainly.com/question/15181104
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From the diagram;
1. Angle 2 = ADB+BDH
= arcAB/2 +90
= 34 +90
= 124°
2. Angle 4= 90°,
Reason ; the angle between a tangent and a radius is equal to 90. A tangent is a line that touches the circumference of a circle once even if prolonged.
3. Angle 5 = 90 -BDC (note the acr subtends twice the angle it subtends on the circumference to the center.
= 90-arc BC/2
= 90-36
= 54°
4. Angle 6 = BFD
= 180-ADB-FBD
= 180-AB/2-DE/2
But DE = 180 -121 = 59
Therefore, BFD = 180 -34-29.5
= 116.5°
5. Angle 1 = 180- BFD (angles on a straight line add up to 180°)
= 180- 116.5
= 63.5°
6. Angle 3 = 180 -(ADB+BFD)
= 180 -(34 +116.5)
= 180- 150.5
= 29.5°
similarly angle 3 = DE/2 = 59/2 = 29.5°
7. Angle 8= 90, because BD is diameter;
angles subtended by a diameter to the circumference is always a right angle (90°)
8.Angle 7 = BE
but BE= AB+AE
= 68+ 53
= 121°
Answer:
False
Step-by-step explanation:
Answer:
Ox>5
x is less than 5
means nothing more than 5 but anything less than 5
Explanation:
Factoring to linear factors generally involves finding the roots of the polynomial.
The two rules that are taught in Algebra courses for finding real roots of polynomials are ...
- Descartes' rule of signs: the number of positive real roots is equal to the number of coefficient sign changes when the polynomial is written in standard form.
- Rational root theorem: possible rational roots will have a numerator magnitude that is a divisor of the constant, and a denominator magnitude that is a divisor of the leading coefficient when the coefficients of the polynomial are rational. (Trial and error will narrow the selection.)
In general, it is a difficult problem to find irrational real factors, and even more difficult to find complex factors. The methods for finding complex factors are not generally taught in beginning Algebra courses, but may be taught in some numerical analysis courses.
Formulas exist for finding the roots of quadratic, cubic, and quartic polynomials. Above 2nd degree, they tend to be difficult to use, and may produce results that are less than easy to use. (The real roots of a cubic may be expressed in terms of cube roots of a complex number, for example.)
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Personally, I find a graphing calculator to be exceptionally useful for finding real roots. A suitable calculator can find irrational roots to calculator precision, and can use that capability to find a pair of complex roots if there is only one such pair.
There are web apps that will find all roots of virtually any polynomial of interest.
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<em>Additional comment</em>
Some algebra courses teach iterative methods for finding real zeros. These can include secant methods, bisection, and Newton's method iteration. There are anomalous cases that make use of these methods somewhat difficult, but they generally can work well if an approximate root value can be found.
