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slava [35]
3 years ago
8

What is the quotient of the following division problem?

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer:

D. 10r7

Explaination:

9 goes into 97 10 times, and has a remainder of 7

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Evaluate the expression for the given value of the variable.
Stels [109]

Answer:

4 * (3 + 5)

4 * 8

<u>32</u>

Step-by-step explanation:

5 0
2 years ago
Verify the identity. cot x / 1 + csc x = csc x - 1 / cot x
svetlana [45]

Step-by-step explanation:

cot x / (1 + csc x)

Multiply by conjugate:

cot x / (1 + csc x) × (1 − csc x) / (1 − csc x)

Distribute the denominator:

cot x (1 − csc x) / (1 − csc²x)

Use Pythagorean identity:

cot x (1 − csc x) / (-cot²x)

Divide:

(csc x − 1) / cot x

5 0
3 years ago
A. 2<br> B. -2<br> C. 1/2<br> D. -1/2
allsm [11]

Rate of change is the slope.

The slope is the change in Y over the change in X:

Slope = (5- -3) / (2 - -2)

Slope = 8/4

Slope = 2

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7 0
2 years ago
Abby has a beginning balance of $720 in her checking account. She writes two checks for $240 and $350 respectively and deposits
Yuliya22 [10]
<span>You made $18.10000000</span>
8 0
3 years ago
Help me on math please really need help
Zanzabum
If the height was 10, then the volume of the cube would be 1000 because you find volume you must multiply the length*width*height and the value of those three is 10. 
Now since volume is 1000 and the volume of a 2in cube is 8 (again, lwh=V) you can divide 1000 by 8 and you would get 125. So that means 125 2in cubes can fit inside the bigger cube.

If the volume of this cube were 750in^3 and you had to find the height, you would use the Volume formula again:
l*w*h=V
10*10*h=750
20h=750
((divide both sides of the equation by 20 to find the value of h))
h=37.5

If the surface area of the cube were 680in^2 then you would use the surface area formula to find the value of h:
(2(lw))+(2(lh))+(2(wh))=A
(2(10*10))+(2(10h))+(2(10h))=680
200+20h+20h=680
subtract 200 from both sides of the equation:
40h=480
divide both sides by 40 to get the value of h:
h=12
5 0
3 years ago
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