<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
Answer:
0.02275
Step-by-step explanation:
We use this z score formula to solve for this question
z-score is is z = (x-μ)/σ/√n
where x is the raw score
μ is the population mean
σ is the population standard deviation
From the above question,
x = 77
μ = 75
σ = 7
number of samples = 49
Hence, the z score = 77 - 75/ (7/√49)
= 2/(7/7)
= 2/1
= 2
Hence, the z score = 2
Using the z table to find probability
P(x<77) = 0.97725
P(x>77) = 1 - P(x<77)
= 1 - 0.97725
= 0.02275
Therefore, the probability that the same mean will be larger than 77 years
is 0.02275
Answer:just order them
Step-by-step explanation:
45 divided by 3 gives you 15 which is the amount of money he spent on the gas and 45 divided by 5 is 9 which is the amount of money he spent on the flowers which means he spent $24 so he has $21 left for the big date.
