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Nadya [2.5K]
3 years ago
5

!!!!!Help!!!!

Mathematics
1 answer:
Alja [10]3 years ago
7 0
The correct answer is y=-13/10x+13 as it matches the graph

Hope this helped :)
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What does the model predict for 1900?
vagabundo [1.1K]

Answer:

64.0% is the correct answer.

Step-by-step explanation:

As per the given scatter plot of voter turnout every year:

X axis represents the year and

Y axis represents the percentage of people who voted.

The model was predicted as per the equation:

y = -0.1271x + 307.53

<u>To find:</u> Prediction for the year 1900.

Putting the value of x=1900, the value of y will be the predicted value of the model i.e. the value of percentage of voter turnout.

\Rightarrow  y = -0.1271\times (1900) + 307.53\\\Rightarrow  y = -241.49 + 307.53\\\Rightarrow  y = -64.04\%\\OR\\y \approx 64.0\%

So, the model predicts y \approx 64.0\% for the year 1900.

3 0
3 years ago
3. If a snail moves
Mila [183]
Hi there!

We know that the snail lives 1 x 1/2 feet in 3 x 3/4 hours. First you have to simplify or solve the expressions. 1 x 1/2 is equal to 1/2 and 3 x 3/4 is 9/4 or 2.25 in decimal form.

You need to divide 2.25 by 1/2 or 0.5 which is 4.5.

So the snail moves 4.5 or 9/2 feet per hour.

Hope this helps !
5 0
3 years ago
the senior class has 350 students. How much is the total bill if the student government wants to buy each senior a T-shirt costi
lorasvet [3.4K]
7.20+24.75=31.95
so 31.95 per student

31.95*350=11,182.50

This will cost the student body $11,182.50 
7 0
3 years ago
Please help it’s geometry! I’ll make brainliest
expeople1 [14]
GX is the angle bisector. Answer is C
4 0
3 years ago
Read 2 more answers
A company has a fleet of 200 vehicles. On average, 50 vehicles per year experience property damage. What is the probability that
ICE Princess25 [194]

Answer:

The probability is \frac{1}{4} or 25%

Step-by-step explanation:

The question states the total number of vehicles, as well as the number of damaged vehicles on a yearly basis. If 50 vehicles in every 200 vehicles per year are damaged, then we can obtain:

Probability of a damaged vehicle in any given year = \frac{Number of Damaged Vehicles}{Total Number of Vehicles}

= \frac{50}{200} = \frac{1}{4} or 25%

4 0
3 years ago
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