Answer:
Is there any other numbers in that equation? I'm sorta confused. ;)
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
1000000 times larger
Step-by-step explanation:
2x10^2 is 200.
2x10^8 is 200000000
2x10^8 is 1000000 times larger that 2x10^2
Answer:
- Average age of the employees in 2003 = 57.216
- Average age of the employees in 2009 = 59.184
Step-by-step explanation:
We are given the function A(s) as;
A(s) = 0.328*s + 50 where s = number of years since 1981; that is,
s = 0 for 1981 and s = 9 for 1990
A(s) = the average age of an employee
- Now, the average age of the employees in 2003, A(22) = 0.328*22 + 50
Here s = 22 because 2003 - 1981 = 22 years
Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .
- Average age of the employees in 2009, A(28) = 0.328*28 + 50
Here, s = 28 because 2009 - 1981 = 28 years
Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .
Answer:
displacement = 75 km
Step-by-step explanation:
the distance from final to initial point gives the displacement
displacement = 120 - 45