To find the derivative, you must use the chain rule.
If u=x^3+2x:
dy/dx=(dy/du)(du/dx)
dy/du=d/du(e^u)=e^u=e^(x^3 + 2x)
du/dx =d/dx (x^3+2x) = 3x^2 + 2
So dy/dx=
e^(x^3+2x) * (3x^2+ 2)
Answer:
Let's begin by writing the mathematical equations given by the sentences.
Let X = smaller number
Let Y = larger number
The first sentence tells us
X + Y = 38
The second sentence tells us
X = Y/3 + 6
Since you weren't given a specific method to use, you can use either the substitution method or the elimination(addition) method, whichever works best for you.
Since the 2nd equation has the X isolated, I'm going to isolate the X in the first equation,
X = 38 - Y
Since both equations are equal to X, I can set them equal to one another and solve for Y.
Y/3 + 6 = 38 - Y
Y + 18 = 114 - 3Y
4Y = 96
Y = 24
Then use either of the two original equations to solve for X
X + Y = 38
X + 24 = 38
X = 14
Step-by-step explanation:
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Answer:
Square
Step-by-step explanation:
