4 divided by 50 to show how much turkey you need for a sand witch

Mathematics

1 answer:

vfiekz [6]3 years ago

5 0

Answer: Non is needed...No turkey is needed for sandwich. Yo

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Which explanation provides the best real-world scenario of the graph? If an object is dropped from a height of 38 feet, the func

ikadub [295]

The equation that models the movement of the object is:
$h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0
$
Where,
t: time
a: acceleration due to gravity
v0: initial speed
h0: initial height
Suppose that the object falls with zero initial velocity and from a height of 38 feet.
The equation that models the problem is:
$h (t) = -16t ^ 2 + 38
$
Answer:
If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds

5 0

3 years ago

What is <br> 6 3/5<br><br> Write your answer as a mixed number.

galina1969 [7]

Answer:

33/5

Step-by-step explanation:

6 3/5 = 33/5

6 x 5 = 30

30 + 3 = 33

33/5.

4 0

3 years ago

Read 2 more answers

A square garden plot measures 180 square feet. A second square garden plot measures 320 square feet. How many more feet of fence

REY [17]

The second garden plot will require 8√5 feet more fence than the first garden plot.

Further explanation:

In order to find the fence, we have to find the perimeter of both squares

So,

Area of Square 1: A1=180 square feet

Area of Square 2: A2=320 Square feet

Let x be the side of square 1:

Then,

$A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}$

For second square:

Let y be the side of second square

$A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}$