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3 years ago

Least to greatest 2.614;2.146;2.46;2.164

Mathematics

2 answers:

sveta [45]3 years ago

7 0

2.146, 2.164, 2.46, 2.614

bixtya [17]3 years ago

4 0

Least to greatest:
2.146
2.164
2.46
2.614
(The 2.46 would be second because although it seems smallest, the 4 in the tenths place is greater than the 1's for the first 2)

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nlexa [21]

Answer:

$P(38.6$

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

$z=\frac{X -\mu}{\sigma}$

And replacing we got:

$z=\frac{38.6- 45}{16}= -0.4$

$z=\frac{57.8- 45}{16}= 0.8$

We can find the probability of interest using the normal standard table and with the following difference:

$P(-0.4$

Step-by-step explanation:

Let X the random variable who represent the expense and we assume the following parameters:

$\mu = 45, \sigma 16$

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

$P(38.6$

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

$z=\frac{X -\mu}{\sigma}$

And replacing we got:

$z=\frac{38.6- 45}{16}= -0.4$

$z=\frac{57.8- 45}{16}= 0.8$

We can find the probability of interest using the normal standard table and with the following difference:

$P(-0.4$

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3 years ago

the diameter of the sweep of the main rotor of the eh101 helicopter is 18.6 meters. A toy model of it has a sweep of 31 centimet

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Answer:

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Step-by-step explanation:

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Now, the toy model of the helicopter has a sweep of 31 cm.

Therefore, the scale in which the model is made is 1860 : 31 i.e. 60 : 1 ratio.

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umka2103 [35]

Answer:

13) 8.6

Step-by-step explanation:

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You have the adjacent side and hypotenuse to the angle. Use the cosine function since its ratio is adjacent over hypotenuse.

This means Cos 52 = x / 14. Solve for x.

Cos 52 = x / 14

14* Cos 52 = x

8.6 = x

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hichkok12 [17]

Answer:

It is the <em><u>second one</u></em>

Step-by-step explanation:

1st option does not include the number 2 from the equation above,

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