The graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
-3x + 5y = -15
The above function shows a linear function we can write it as:
5y = 3x - 15
y = (3x - 15)/5
If x = 0, y = -3
x = 1, y = -2.4
x = 2, y = -1.8
x = -1, y = -3.6
x = -2, y = -4.2
Thus, the graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.
Learn more about the function here:
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Answer:
- (x + 10)² + (y + 4)² = 232
Step-by-step explanation:
<h3>Given </h3>
- Center = (-10, -4)
- Point on circle = (4, 2)
<h3>To find </h3>
<h3>Solution</h3>
<u>Remember the standard equation of circle:</u>
- (x - h)² + (y - k)² = r², where (h, k) is the center and r is radius
<u>We have</u>
Use distance formula (Pythagorean theorem) to work out the length of the radius. We know that radius is the distance from the center to any point on the circle.
<u>Here we are finding the distance between points (-10, -4) and (4, 2)</u>
- r² = (-10 - 4)² + (-4 - 2)²
- r² = 14² + 6²
- r² = 232
<u>So the equation is:</u>
- (x + 10)² + (y + 4)² = 232
Step-by-step explanation:
the surface area consists of 6 individual areas :
front and back (both are equal)
left and right (both are equal)
top and bottom
front and back are trapezoids.
the area of a trapezoid is
(base 1 + base 2)/2 × h
the bases are the 2 parallel sides.
in our case the area of one trapezoid is
(5 + 19)/2 × 12.1 = 145.2 ft²
front and back together then are 290.4 ft².
left and right are 8×14 rectangles:
8×14 = 112 ft²
together they are 224 ft².
the bottom is a 5×8 rectangle :
5×8 = 40 ft²
the top is a 19×8 rectangle :
19×8 = 152 ft²
so, the total surface area is
290.4 + 224 + 40 + 152 = 706.4 ft²
L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
