area of a square field is 1600 square metre. find the cost of boundary wall if the rate of per metre is Rs. 500

Mathematics

1 answer:

slavikrds [6]2 years ago

7 0

Answer:

Rs. 20,000

Step-by-step explanation:

the boundary wall will act as a perimeter.

the perimeter of a square field is 4S( S = side)

S x S = area

S2 = area

S =

square root of S2= square root of area

square root of S2 = S

S = square root of area

S = square root of 1600

S = 40m

perimeter = 4 x S

= 4 x 40

= 160m

1m = rs. 500

40m = 40m x rs.500

=Rs. 20,000

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Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

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(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$