3 years ago

Order the rational numbers from least to greatest.

Mathematics

1 answer:

Verdich [7]3 years ago

7 0

Answer:

d. -7 1/8, -3.62, -1/2, 0, 1.75

Step-by-step explanation:

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A gardener has 10 pounds of soil. He used 58 of the soil for his garden. How many pounds of soil did he use in his garden?

mars1129 [50]

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Step-by-step explanation:

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3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

Marina86 [1]

Area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

$$=\frac{1}{4} \pi r^2 - \frac{1}{2} bh$

$$=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times 12 \times 12$

$$=36\pi -72$

$$=36(\pi -2)$ square cm.

Area of the shaded region $$=36(\pi -2)$ square cm

Using Pythagoras theorem,

$AC^2=AB^2+BC^2$

$AC^2=12^2+12^2$

$AC^2=288$

Taking square root on both sides of the equation, we get

$AC= 12\sqrt 2$ cm

Perimeter of the quadrant of a circle = $\frac{1}{4} \times 2\pi r$

$$=\frac{1}{4} \times 2 \times \pi \times 12$

$$=6 \pi$ cm

Perimeter of the shaded region = $6 \pi + 12\sqrt 2$ cm

$=6 (\pi + 2\sqrt 2)$ cm

Hence area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

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3 years ago

Multiply and simplify <br> square root of 3ab * square root of 6ab^3<br><br> NEED HELP FAST!!!!!!

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3 years ago

BRAINILIST TO FIRST PERSON TO ANSWER AND GET IT CORRECT!!! please answer fast!

miv72 [106K]

The answer would be 4 divided by 2/3 = 6 tiles

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1/3(x+4)=20 need help

sukhopar [10]

1/3(x+4)=20

1/3x+4/3=20

1/3x=56/3

x= (56/3) / (1/3)

x= 56

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3 years ago

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