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Sedaia [141]
3 years ago
9

A 5.00 g piece of metal is heated to 100.0 C then placed in a beaker containing 20.0 g of water at 10.0 C. The temperature of th

e water rises to 15.0 C. Calculate the specific heat of the metal
Chemistry
1 answer:
Nataly [62]3 years ago
5 0
Calculate the heat gained by the water first.

q = mCpΔT
m = 20.0 g
Cp = 4.186 J/g°C
ΔT = T(final) - T(initial) = 15.0°C - 10.0°C = 5.0°C

q = (20.0)(4.186)(5.0) = 419 J

This is equal to the heat lost by the metal, so calculate Cp for the metal, given:
q = -419 J (negative because heat was lost)
m = 5.00 g
ΔT = 15.0°C - 100.0°C = -85.0°C (negative because the temperature decreased)

q = mCpΔT —> Solve for Cp —> Cp = q/mΔT

Cp = -419 / (5.00 • -85.0) = 0.986 J/g°C
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....."W is positive if work is done by the system"........

and negative if work is done on the system.


So, work done by a system is positive.
6 0
3 years ago
I need for a test and explain please
Shkiper50 [21]

Answer:

0.200M H₃PO₄

0.600N H₃PO₄

pH = 1.46

Explanation:

The acid-base reaction of phosphoric acid (H₃PO₄) with LiOH is:

3 LiOH + H₃PO₄ → Li₃PO₄ + 3H₂O

<em>Where 3 moles of LiOH reacts per mole of H₃PO₄</em>

<em />

Moles of LiOH are:

0.030L× (0.5mol / L) = 0.0150 moles of LiOH

Moles of acid neutralized are:

0.0150 moles of LiOH × (1 mole H₃PO₄ / 3 moles LiOH) = 0.005 moles H₃PO₄

As volume of acid was 25mL, molarity is:

0.005mol H₃PO₄ / 0.025L =<em> 0.200M H₃PO₄</em>

Normality is:

0.200M × (3N H⁺ / 1M H₃PO₄) = <em>0.600N H₃PO₄</em>

H₃PO₄ dissolves in water thus:

H₃PO₄ ⇄ H₂PO₄⁻ + H⁺

Ka = 7.1x10⁻³ = [H₂PO₄⁻] [H⁺] / [H₃PO₄]

Where molar concentrations in equilibrium will be:

[H₂PO₄⁻] = X

[H⁺] = X

[H₃PO₄] = 0.200M - X

Replacing in Ka formula:

7.1x10⁻³ = [X] [X] / [0.200 - X]

1.42x10⁻³ - 7.1x10⁻³X = X²

0 = X² + 7.1x10⁻³X - 1.42x10⁻³

Solving for X:

X = -0.04M →False answer, there is no negative concentrations.

X = 0.0343M

As, [H⁺] = 0.0343M

pH = - log [H⁺],

<em>pH = 1.46</em>

6 0
3 years ago
A piece of neutral litmus paper turned red in some grapefruit juice.  What does this show about the grapefruit juice
Elodia [21]

Answer:

grapefruit juice is an acid

Explanation:

A piece of neutral litmus paper turned red in some grapefruit juice.  What does this show about the grapefruit juice

with litmus paper remember:

E     R          

S     E

ACID

BLUE

acids turn litmus red, bases turn it blue

all citrus fruits :llemons, lime, grapefruit, oranges, etc are called

CITRUS FRUITS because they contain citric acid

7 0
2 years ago
In order to be sure that your results are accurate, you must be able to ______ your experiment.
mina [271]
The answer is A, you must repeat your experiment to ensure you results are accurate. That is the best way to know for sure and it is what you must do to every experiment.  
7 0
3 years ago
What is the name of the opposite stereoisomer of the molecule shown below?
NikAS [45]

Answer:

the answer is d hope this helps

and dont forget to mark me as brainliest

Explanation:

3 0
3 years ago
Read 2 more answers
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