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3 years ago

How did satellite tracking allow biologists to study the green sea turtle?

Chemistry

2 answers:

Thepotemich [5.8K]3 years ago

5 0

Answer:

D.It helped biologists collect data on when and where turtles travel.

Rasek [7]3 years ago

4 0

Answer:

It helped biologists collect data on when and where turtles travel.

Explanation:

Green sea turtles need to be conserved so the biologist take help of satellites in order to track down green sea turtles.

The tracking of green sea turtles can be done by the help of satellites as satellites send a signal whenever these turtles come to surface of water to breathe which can then be used to prevent the turtles from getting caught by poachers.

You might be interested in

Determine the specific heat of a 213.0 g piece of metal in J/g•°C if the temperature of the metal drops from 70.2 °C to 25.6 °C

ladessa [460]

Answer:

0.3415 J/g °C

Explanation:

M1 = 213.0g

c1 = ?

T1 = 70.2°C

T3 = 25.6 °C

T2 = 22.5°C

C2 = 4.186 J/g°C

Vol. of water = 250mL = 250cm³

p (density of water ) = 1g/L

p = mass / volume

mass (m) = density (p) * volume (v)

m = 1 * 250 = 250g

Heat loss by metal = heat gain by water

Q1 = Q2

Mc∇T = Mc∇T

Mc (T1 - T3) = Mc* (T3 - T2)

213 * c * (70.2 - 25.6) = 250 * 4.186 * (25.6 - 22.5)

(213 * 44.6)c = 1046.5 * 3.1

9499c = 3244.15

c = 0.3415 J/g.°C

The specific heat capacity of the metal is 0.3415 J/g °C

3 0

4 years ago

The density of solid Ag is 10.5 g/cm3. How many atoms are present per cubic centimeter of Ag?

Sveta_85 [38]

Answer:

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

Edge length = $4.1\times 10^{-8}\ cm$

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = $\frac{10.5\ g/cm^3}{107.8682\ g/mol}$ =0.0973 mol/cm³

Also, 1 mole = $6.023\times 10^{23}$ atoms.

So,

Atoms present per cm³ of Ag = $0.0973\ mol/cm^3\times 6.023\times 10^{23}\ atoms/mol=5.8\times 10^{22}\ atoms/cm^3$

Thus, answer = $5.8\times 10^{22}\ atoms/cm^3$

In FCC, the number of atoms in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag = $\frac{5.8\times 10^{22}\ atoms/cm^3}{4}=1.45\times 10^{22}\ unit\ cells /cm^3$

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So, $Volume=\frac{1}{1.45\times 10^{22}\ unit\ cells /cm^3}=68.9\times 10^{-24}\ cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

(c)

Also, Volume = ${(Edge\ length)}^3$

Thus, edge length = ${Volume}^{\frac{1}{3}}$ = $\left(68.9\times \:\:10^{-24}\right)^{\frac{1}{3}}\ cm=4.1\times 10^{-8}\ cm$

Edge length = $4.1\times 10^{-8}\ cm$

5 0

4 years ago

How is thermal energy transferred during conduction? Check all that apply.

Dvinal [7]

Answer:

Thermal energy is transferred between particles that are in direct contact with each other.

Thermal energy is transferred between objects of different temperatures.

Thermal energy is transferred from fast-moving particles to slow-moving particles.

Explanation:

5 0

3 years ago

Calculate the wavelength and frequency of an emitted photon of gamma radiation that has energy of 3.02 × 1011 J/mol.

maks197457 [2]

The wavelength is 4.0 * 10^-13 m while the frequency is 7.5 * 10^20 s−1

Using the formula;

E =hf

Where

E = Energy of the photon

f = Frequency of photon

h = Plank's constant = 6.6 * 10^-34 Js

To obtain the energy in Joules;

E = 3.02 × 10^11 J/mol/6.02 * 10^23 mol

= 5 * 10^-13 J

f = E/h

f = 5 * 10^-13 J/6.6 * 10^-34 Js

f = 7.5 * 10^20 s−1

f = c/λ

c = speed of light = 3 * 10^8 m/s

λ = c/f

λ = 3 * 10^8 m/s/7.5 * 10^20 s−1

λ = 4.0 * 10^-13 m

The wavelength is 4.0 * 10^-13 m while the frequency is 7.5 * 10^20 s−1

Learn more: brainly.com/question/2393994

6 0

3 years ago

What is the term for the outer electron shell of an atom?

Musya8 [376]

The correct answer is D. Valence

4 0

3 years ago