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Sunny_sXe [5.5K]

2 years ago

10

In what ways are the two designs in part C different? How do you think these differences will relate to the ability of each desi

gn to heat up? Which design do you think will heat up the best?

1 answer:

Ilya [14]2 years ago

4 0

The top one is different from the bottom because of is curvature shape while the bottom one is a square shape i think the bottom will heat up faster because of the nice even area inside where heat waves can evenly flow

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At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

Alekssandra [29.7K]

Explanation:

$Density =\frac{Mass}[Volume}$

Density of the air ,d= 1.189 g/L

(a) Density of the evacuated ball

Mass of the ball ,m = 0.12 g

Volume of the ball = $V=560 cm^3=560 ml=0.560 L$

$D =\frac{0.12 g}{0.560 L}=0.214 g/L$

D<d, teh evacuated ball will flaot in air.

(b) Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = $d_1=1.830 g/L$

Mass of the carbon dioxide gas :

$1.830 g/L\times 0.560 L=1.0248 g$

Total density of filled ball with carbon dioxide gas:

$\frac{0.12 g+1.0248 g}{0.560 L}==2.044 g/L$

The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air.

(c) Density of the evacuated ball D = 0.214 g/L

Density of hydrogen gas = $d_2=0.0899 g/L$

Mass of the hydrogen gas :

$1.830 g/L\times 0.560 L=0.050344 g$

Total density of filled ball with hydrogen gas:

$\frac{0.12 g+0.050344 g}{0.560 L}==0.3041 g/L$

The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

(d) Density of the evacuated ball D = 0.214 g/L

Density of oxygen gas = $d_3=1.330 g/L$

Mass of the oxygen gas :

$1.330 g/L\times 0.560 L=1.7448 g$

Total density of filled ball with oxygen gas:

$\frac{0.12 g+1.7448 g}{0.560 L}=1.5442 g/L$

The ball filled with oxygen will not float in the air because total density of filled ball is greater than the density of an air.

(e) Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = $d_4=1.165 g/L$

Mass of the nitrogen gas :

$1.165 g/L\times 0.560 L=0.6524 g$

Total density of filled ball with nitrogen gas:

$\frac{0.12 g+0.6524 g}{0.560 L}==1.3792 g/L$

The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air.

f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

$\frac{0.12g +m}{0.560L}>1.189 g/L$

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

5 0

2 years ago

Which of the following describes the role of water in supporting the chemical reactions that occur within various life forms? It

wel

Answer:

The correct option is;

It is used during photosynthesis to capture sunlight

Explanation:

During photosynthesis, light energy from the Sun is converted and stored in sugars as chemical energy. The Sun light energy is used in the formation of complex sugars such as glucose from the combination of water from the ground and carbon dioxide from the atmosphere while oxygen is released as the byproduct. Organisms are then able to obtain energy from the glucose as well as carbon fiber

The chemical equation for the reaction is as follows;

6CO₂ + 12H₂O + light energy → C₂H₁₂O₆ + 6O₂ + 6H₂O

Carbon, Water, GLucose, Oxygen, Water

dioxide

4 0

3 years ago

Read 2 more answers

0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of t

alina1380 [7]

Answer:

$M=6.03M$

Explanation:

Hello,

In this case, since the molarity is computed by:

$M=\frac{n_{solute}}{V_{solution}}$

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

$n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl$

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

$V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L$

Therefore, the molarity turns out:

$M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M$

Regards.

6 0

3 years ago

PUTTING MAX POINTS

Delicious77 [7]

The first one is correct because one mole of oxygen is half of 2O2 so it is half of the energy

it absorbs because the negative sign indicates energy taken inside

hope this helps

8 0

2 years ago

Read 2 more answers

An aqueous solution of hydrobromic acid is standardized by titration with a 0.164 M solution of calcium hydroxide. If 14.9 mL of

Arada [10]

Answer:

The molarity of hydrobromic acid is 0.182 M

Explanation:

Step 1: Data given

Molarity of Calcium hydroxide = 0.164 M

Volume of calcium hydroxide = 14.9 mL = 0.0149 L

Volume of HBr = 26.9 mL = 0.0269 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr →CaBr2 + 2H2O

Step 3: Calculate molarity of HBr

b*Ca*Va = a*Cb*Vb

⇒b = the coefficient of HBr = 2

⇒Ca = the molarity of Ca(OH)2 = 0.164 M

⇒Va = the volume of ca(OH)2 = 0.0149 L

⇒a= the coefficient of Ca(OH)2 = 1

⇒Cb = the molarity of HBr = TO BE DETERMINED

⇒Vb = the volume of HBr = 0.0269 L

2*0.164 * 0.0149 = 1*Cb*0.0269

Cb = 0.182 M

The molarity of hydrobromic acid is 0.182 M

6 0

3 years ago