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kirill [66]
2 years ago
14

A line passes through the points (-15, 4) and (5,8). What is its equation in slope-intercept

Mathematics
1 answer:
vovangra [49]2 years ago
7 0

Answer:

y=1/5x+7

Step-by-step explanation:

just checked it on paper

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Answer:

D. 48

Step-by-step explanation:

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Answer:

C

Step-by-step explanation:

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3 years ago
Please help thanks so much
Goshia [24]

Answer:

<em>y = (-4/3)*x + 7</em>

<em />

Step-by-step explanation:

The point-slope form of the equation of a line is: <em>y = a*x + b </em>

In the above equation, <em>a </em>is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]

The given line has a slope of -4/3, so that <em>a = -4/3 </em>

=> The equation of this line has a form as following: <em>y = (-4/3)*x + b (1)</em>

<em />

As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:

<em>y = (-4/3)*x + b</em>

<em>=> -5 = (-4/3)*9 + b </em>

<em>=> -5 = -12 + b </em>

<em>=> b = 7</em>

<em />

So that the equation in point-slope form of the given line is:

<em>y = (-4/3)*x + 7</em>

<em />

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Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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