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3 years ago

Help help help help!!!!!

Mathematics

2 answers:

Vesnalui [34]3 years ago

5 0

A=w•l
w=x+1
l=x+7
A=(x+1) •(x+7)
A=x^2+7x+x+7
A=x^2+8x+7

Art [367]3 years ago

3 0

Area is equal to length times width, so we can use this over here:

Area = lw
Area = (x+7)(x+1)
Area = x^2+x+7x+7
Area = x^2+8x+7

Hope this helps!! :)

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I don’t understand this subject at all if you wold answer that would be a big help

Digiron [165]

Answer:

d= 8.6 ft

Step-by-step explanation:

In similar triangles, the corresponding sides are in proportion.

$\boxed{\dfrac{AW}{MZ}=\dfrac{AJ}{MJ}=\dfrac{WJ}{ZJ}}$

To find the value of x,

$\dfrac{AJ}{MJ}=\dfrac{WJ}{ZJ}\\\\\\\dfrac{6}{7}=\dfrac{d}{10}\\\\\\\dfrac{6}{7}*10=d$

d = 8.6 ft

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2 years ago

What’s the value of <br> tan (3arc cos 3/4)

Volgvan

<h2>Answer: -1.469</h2>

This trigonometric function can be written as:

$tan (3 cos^{-1} (\frac{3}{4}))$ (1)

Firstly, we have to solve the inner parenthesis:

$cos^{-1} (\frac{3}{4})= 41.409$ (2)

Substituting (2) in (1):

$tan (3(41.409))=tan(124.228)$ (4)

Finally we obtain the value:

$tan(124.228)=-1.469$

6 0

2 years ago

Read 2 more answers

Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?

9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

$f(x)=\frac{(x-1)(x^2-4)}{x^2-a}$

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that $x=\sqrt{a}$ will annulate the denominator, i.e

$(\sqrt{a})^2-a = a-a = 0$ . But, if a = 1 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}$

so, the value $x=\sqrt{a} = \sqrt{1} = 1$ won't annulate the denominator.

Now, for a = 4 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1$

so, the value $x=\sqrt{a} = \sqrt{4} = 2$ won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0

3 years ago

Find the circumference to the nearest tenth

gregori [183]

C=3.14(15.6)
C=48.9-> 49

4 0

3 years ago

what is the measure of the base angle,x, of the isosceles triangle shown below? round your answer to the nearest tenth of a degr

MAVERICK [17]

Answer:

x ≈ 49.7°

Step-by-step explanation:

Since, the given triangle is an isosceles triangle,

Two sides having measure 17 units are equal.

Opposite angles of these equal sides will be equal.

Measure of the third angle = 180° - (x + x)°

By sine rule,

$\frac{\text{sinx}}{17}=\frac{\text{sin}(180-2x)}{22}$

$\frac{\text{sinx}}{17}=\frac{\text{sin}(2x)}{22}$ [Since, sin(180 - θ) = sinθ]

$\frac{\text{sinx}}{17}=\frac{2(\text{sin}x)(\text{cos}x)}{22}$

$\frac{\text{sinx}}{17}=\frac{(\text{sin}x)(\text{cos}x)}{11}$

$\frac{1}{17}=\frac{(\text{cos}x)}{11}$

cos(x) = $\frac{11}{17}$

x = 49.68°

x ≈ 49.7°

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3 years ago